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Stolb23 [73]
3 years ago
9

Two balls of equal size are dropped from the same height from the roof of a building. One ball has twice the mass of the other.

When the balls reach the ground, how do the kinetic energies of the two balls compare
Physics
1 answer:
frutty [35]3 years ago
3 0

Answer:

The kinetic energy of the more massive ball is greater by a factor of 2.

Explanation:

By conservation of energy, we know that the initial energy = final energy. At first, the balls are dropped from a height with no initial velocity so their initial energy is all potential energy. When they reach the bottom, all their energy is kinetic energy. So all of their energy is changed from potential to kinetic energy. This means that the ball with greater potential energy will have a greater kinetic energy.

Potential energy = mgh. Since g = gravity is a constant and h = height is the same, the only difference is mass. Since mass is directly proportional to potential energy, the greater the mass, the greater the potential energy, so the more massive ball has a greater initial potential energy and will have a greater kinetic energy at the bottom.

Additionally, let B1 = lighter ball with mass m and let B2 = heavier ball with mass m2. Since we know that intial potential energy = final kinetic energy. We can rewrite it as potential energy = kinetic energy = mass * gravity constant * height. For B1, it is mgh and for B2 it is 2mgh, so B2's kinetic energy is twice that of B1.

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A water wave travels 36 meters in 15 seconds. What is the speed of the wave?
Arisa [49]
Since the question above is looking for the SPEEd of the WAVE, the formula that should be used is SPEED = DISTANCE / TIME. You just need to substitute the distance (36 meters) and the time (15 seconds) to the formula. You should be able to get SPEED = 2.4 m/s.
4 0
4 years ago
Read 2 more answers
A 384 m long train is moving on a straight track with a speed of 77.3 km/h. The engineer applies the brakes at a crossing, and l
solniwko [45]

Answer:

The time the train blocked the crossway is

0.007934h=0.476 min=28.6 s

Explanation:

The average speed is given by

V= (Vi+Vf)/2

and

V= dx/dt

Where

Vi= initial speed

Vf= final speed

dx= change of position=0.384 km

dt=time the train blocked the crossway

dt=2dx/(Vi+Vf)

dt=2*0.384 km/(77.3 +19.5) km/h

dt=0.007934h

dt=0.007934h*(60min/1h)=0.476 min

dt=0.476 min*(60s/1min)=28.6 s

7 0
3 years ago
What is the relationship between velocity and kinetic energy?
faltersainse [42]

Answer:

when an object has more velocity, it tends to have less potential energy and more kinetic energy.

Explanation:

kinetic energy is the energy of movment and velocity helps to describe movement

4 0
4 years ago
Electric discharge between two objects follows a predictable path?
LenaWriter [7]

Answer: YES

They always move towards the earth or any metallic conductor

Explanation:

Electric discharge between two objects follows a predictable path? YES

Static electricity is a buildup of electric charges on objects. Charges build up when negative electrons are transferred from one object to another. The object that gives up electrons becomes positively charged, and the object that accepts the electrons becomes negatively charged.

Once an object becomes electrically charged, it is likely to remain charged until it touches another object or at least comes very close to another object. That’s because electric charges cannot travel easily through air, especially if the air is dry.

They always move towards the earth or any metallic conductor

7 0
3 years ago
An important news announcement is transmitted by radio waves to people who are 82 km away, sitting next to their radios, and by
Viktor [21]

Answer:

13.5 ms

Explanation:

The sound wave travels with uniform motion in both cases, so the time taken to cover a distance d is given by:

t=\frac{d}{v}

where

d is the distance to cover

v = 340 m/s is the speed of sound in air

So for the people across the newsroom,

d = 4.7 m

So the time taken is

t=\frac{4.7}{340}=0.0138 s = 13.8 ms

The radio waves instead travels with uniform motion at the speed of light:

c=3.0\cdot 10^8 m/s

So the time taken for them is

t=\frac{d}{c}

where

d = 82 km = 82,000 m

is the distance of the people who are 82 km away. Substituting,

t=\frac{82,000}{3.0\cdot 10^8}=0.27\cdot 10^{-3} s = 0.27 ms

Therefore, the difference in time is

\Delta t = 13.8 ms - 0.27 ms = 13.5 ms

4 0
3 years ago
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