The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
<h3>Hooke's Law</h3>
Hooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.
To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.
Formula:
- F = ke................. Equation 1
Where:
- F = Force applied
- k = Spring constant
- e = extension
make k the subject of the equation
- k = F/e................ Equation 2
From the question,
Given:
- F = 450 N
- e = 30 cm = 0.3 m
Substitute these values into equation 2
Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.
- W = ke²/2........... Equation 3
Where:
- W = Work done
- k = spring constant
- e = extension
Also, From the question,
Given:
- e = (80-50) = 30 cm = 0.3 m
- k = 1500 N/m
Substitute these values into equation 3
- W = 1500(0.3²)/2
- W = 67.5 J.
Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
Learn more about Hooke's law here: brainly.com/question/12253978
Answer:
Object 2 has the larger drag coefficient
Explanation:
The drag force, D, is given by the equation:
Object 1 has twice the diameter of object 2.
If
Area of object 2,
Area of object 1:
Since all other parameters are still the same except the drag coefficient:
For object 1:
For object 2:
Since the drag force for the two objects are the same:
Obviously from the equation above, c₂ is larger than c₁, this means that object 2 has the larger drag coefficient
Since we are given the equation P = I2R and the measures of variables in the equation, our first step is to identify each variable.
Since there is a resistance of 30 ohms,
R = 30Ω
.
Since there is
power of 2 watts,
P = 2 W.
The variable we are trying to solve for is
I, current.
Now we can plug the given information into the equation and solve for I:
Current (I) = 1/30 A, or
0.033 A.
Hope this helps!
the answer is 1.5 hope this helps