1) we find out the equation of the line.
Given a point (x₀,y₀) and the slope m, the slope-point form is:
y-y₀=m(x-x₀)
Data:
(3,4)
m=6
Therefore:
y-4=6(x-3)
y-4=6x-18
y=6x-18+4
y=6x-14
2) we find out y, when x=27
y=6*(27)-14
y=162-14
y=148
Answer: When x=27, then y=148.
This cannot be expressed as an answer but the expression for that is 3L-5
Answer:
y = (1.5x + 8)/6
Step-by-step explanation:
6y - 1.5x = 8
+1.5x +1.5x
6y = 1.5x + 8
---- ------------
6 6
y = (1.5x + 8)/6
Answer:
2
Step-by-step explanation:
4x = 32 - x2 would be much clearer if written as 4x = 32 - x^2. Please use
" ^ " to indicate exponentiation.
Rewrite 4x = 32 - x^2 in the standard form of a quadratic: x^2 + 4x - 32
Then the coefficients are a = 1, b = 4 and c = -32.
Find the discriminant. It is b^2-4ac.
Here, b^2-4ac = 4^2 - 4(1)(-32), or 16 + 128, or 144.
Because the discriminant is positive, we know immediately that this quadratic has two real, unequal roots.
So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."