Identify the correct solution for -10+(-16)-10

Usimov [2.4K]

Incomplete question please add a image

5 0

3 years ago

TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin

IRINA_888 [86]

Answer:

a)

[0.5235, 0.5765]

To interpret this result, we could say there is a 99% of probability that the proportion of American adults who have watched digitally streamed TV programming on some type of device is between 52.35% and 57.65%

b) 1,843 American adults

Step-by-step explanation:

The 99% confidence interval is given by

$\bf p\pm z^*\sqrt{p(1-p)/n}$

where

p = the proportion of American adults surveyed who said they have watched digitally streamed TV programming on some type of device = 55% = 0.55

$\bf z^*$ the z-score for a 99% confidence level associated with the Normal distribution N(0,1). We can do this given that the sample size (2,341) is big enough

n = sample size = 2,341

We can find the $\bf z^*$ value either with a table or with a spreadsheet.

In Excel use NORM.INV(0.995,0,1)

In OpenOffice Calc use NORMINV(0.995;0;1)

We get a value of $\bf z*$ = 2.576

and our 99% confidence interval is

$\bf 0.55\pm 2.576\sqrt{0.55*0.45/2341}=0.55\pm 2.576*0.0103=0.55\pm 0.265 = [0.5235, 0.5765]$

To interpret this result, we could say there is a 99% of probability that the proportion of American adults who have watched digitally streamed TV programming on some type of device is between 52.35% and 57.65%

We are 99% confident that this interval contains the true population proportion.

(b) What sample size would be required for the width of a 99% CI to be at most 0.03 irrespective of the value of p?? (Round your answer up to the nearest integer.)

The sample size n in a simple random sampling is given by

$\bf n=\frac{(z^*)^2p(1-p)}{e^2}$

where

e is the error proportion = 0.03

hence

$\bf n=\frac{(2.576)^2p(1-p)}{(0.03)^2}=7373.0844p(1-p)=7373.0844p-7373.044p^2$

taking the derivative with respect to p, we get

n'(p)=7373.0844-2*7373.0844p

and

n'(p) = 0 when p=0.5

By taking the second derivative we see n''(p)<0, so p=0.5 is a maximum of n

This means that if we set p=0.5, we get the maximum sample size for the confidence level required for the proportion error 0.03

Replacing p with 0.5 in the formula for the sample size we get

$\bf n=7373.0844*0.5-7373.044(0.5)^2=1,844$

rounded up to the nearest integer.

6 0

4 years ago

Read 2 more answers

A snail crawls 24 inches in 8 minutes. What is the unit rate of the snail's movement?

trasher [3.6K]

Answer:

3 unit

Step-by-step explanation:

plsss give me brainliest plzzzzzz

3 0

3 years ago

Mr. Wells tells his class of 24 that when they completed the assignment, they may play online math games. At the end of class, 4

QveST [7]

Hello there! Your answer is approximately 14 students.

To solve this question, you want to start by finding 40% of 24. To do this, convert 40% into a decimal (divide by 100) and multiply by 24.

24 x 0.40 = 9.6.

But - you can't have 9.6 of a student. So, we round up to 10.

Note that the question asks how many students still need to complete their assignment, meaning we are looking for the ones that haven't finished. We found the amount for students that have finished, so subtract that from the total to see approximately how many still have to finish.

24 - 10 = 14

So, this means approximately 14 students still need to complete their assignment.

I hope I could help you, have a great rest of your day! :D

3 0

4 years ago

Complete the table for the relationship shown in the graph

Sonja [21]

Answer:

where ?

Step-by-step explanation:

where is the question to solve ?

6 0

3 years ago