Answer:
Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.
Explanation:
Inertia describes the resistance of an object to any change in its state of motion, and it depends on the mass of the object only. In particular:
- if an object has a large inertia (large mass), then it is more difficult to change its state of motion (i.e. to put it in motion, or to slow it down, or to change its direction of motion)
- if an object has small inertia (small mass), then it is more easy to change its state of motion
In this problem, Li has less mass than Raj, so he has less inertia, therefore he can change his motion more easily than Raj.
Answer:
Explanation:
It is assumed that pole vaulter began running at a height of zero. The physical model is formed after the Principle of Energy Conservation:
The previous expression is simplified and required height is found:
![h_{B} = \frac{1}{2 \cdot (9.807\, \frac{m}{s^{2}} )} \cdot [(10\, \frac{m}{s} )^{2}-(1.3\, \frac{m}{s} )^{2}]](https://tex.z-dn.net/?f=h_%7BB%7D%20%3D%20%5Cfrac%7B1%7D%7B2%20%5Ccdot%20%289.807%5C%2C%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29%7D%20%5Ccdot%20%5B%2810%5C%2C%20%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D-%281.3%5C%2C%20%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%5D)
Answer:
8.85
Explanation:
The computation of the charge that must place on them in order to create 1000 N/C field between the plates is shown below:
We know that
E = (Q/A) ÷ E_o
1000 = Q ÷ 0.01×8.85× 10^-12
Q = 8.85 × 10^-12
So,
The answer is 8.85
The above formula should be applied so that the correct value could come
And, the same would be relevant
Answer:
a)
b)
c) Therefore it is a nonconservative force
Explanation:
Distance traveled in one complete circular trip against friction
The force of friction is
The work of friction is the force of friction in the distance so
a).
b).
c).
Since the circle returns to its initial position in both cases and the work done by the friction force different in both cases, so the friction force does depend on the path;
The position of the sun must be at the horizon in order for the rainbow to appear.
The relative positions of the sun and plane make the rainbow appear as a full circle.
However, if the sun is at the horizon, the shadow of the plane will be behind the plane, not below it; this means that the shadow of the plane will not fall on the earth.
