5m
Explanation:
Given parameters:
Energy = 35J
Force on object = 7N
Unknown:
Distance moved = ?
Solution:
The energy on the car will cause the car to do work . When work is done, a force moves a body in particular distance. We can see that energy and force are related:
Energy = force x distance
Distance = 
Inputting the parameters:
Distance = 
= 5m
Learn more:
Work done brainly.com/question/9100769
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<span>We know that the first ball has a mass of 3.1 kg and moves at speed called V1
The second ball has a mass of M2 unknown and the both together moves a speed equal to V = V1/3
The momentum keeps constant before and after balls collide, so:
M1*V1 + M2*V2 = M*V
3.1*V1 + M2*0 = (3.1+M2)*V1/3
3.1*V1 = 3.1/3*V1+M2*V1/3
3.1*V1-3.1/3*V1 = M2*V1/3
(3.1-3.1/3)*V1 = M2*V1/3
2*3.1/3 = M2/3
M2 = 6.2
Then the mass of the second ball is 6.2 kg</span>
Answer:
a) T = (m1cT1 + m2cT2 - m2Lf)/(m1c + m2c)
b) T = 295.37 K
Explanation:
Given;
Initial temperature of tea T1 = 31 C
Initial temperature of ice T2 = 0 C
Mass of tea m1 = 0.89 kg
Mass of ice m2 = 0.075kg
The heat capacity of both water and tea c = 4186 J/(kg⋅K)
the latent heat of fusion for water is Lf = 33.5 × 10^4 J/kg
And T = the final temperature of the mixture
Heat loss by tea = heat gained by ice
m1c∆T1 = m2c∆T2 + m2Lf
m1c(T1-T) = m2c(T-T2) + m2Lf
m1cT1 - m1cT = m2cT - m2cT2 + m2Lf
m1cT + m2cT = m1cT1 + m2cT2 - m2Lf
T(m1c + m2c) = m1cT1 + m2cT2 - m2Lf
T = (m1cT1 + m2cT2 - m2Lf)/(m1c + m2c)
Substituting the values;
T = (m1cT1 + m2cT2 - m2Lf)/(m1c + m2c)
T = (0.89×4186×31 + 0.075×4186×0 - 0.075×33.5 × 10^4)/(0.89×4186 + 0.075×4186)
T = 22.37 °C
T = 273 + 22.37 K
T = 295.37 K
A ball is thrown straight up with an initial velocity of 15 meters per second. How long will it take to drop 10 meters from its initial position?
