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Leona [35]
3 years ago
14

A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont

al and has a tension of 4 N. If you move the end of the rope back and forth, you produce a transverse wave in the rope with a wave speed of 2 m/s. If you double the amount of tension you exert on the rope, what is the wave speed?
Physics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

v' = 2.83 m/s

Explanation:

Velocity of wave in stretched string is given by the formula

v = \sqrt{\frac{T}{\mu}}

here we know that

T = 4 N

also we know that linear mass density is given as

\mu = 1 kg/m

so we have

v = \sqrt{\frac{4}{1}} = 2 m/s

now the tension in the string is double

so the velocity is given as

v' = \sqrt{\frac{8}{1}} = 2\sqrt2 m/s

v' = 2.83 m/s

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Answer: angular displacement in rad = 3038.45 rad

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33.5 = angular displacement /90.7

Angular displacement = 33.5 * 90.7 = 3038.45 rad

But 1 rev =2π

Hence 3038.45 rad to rev is

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3 years ago
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Explanation:

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According to this, if we observe the rays  A an D passing throgh the biconcave lens, we will have two mediums:

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2)The material of the biconcave lens

This two mediums have different refractive indexes, hence the rays will change the direction.

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Light of wavelength 597 nm falls on a double slit, and the first bright fringe of the interference pattern is seen at an angle o
Kazeer [188]

Answer:

2.2 µm

Explanation:

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d\times sin\theta=m\times \lambda

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d is the distance between the slits.

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d=2192.43481\ nm

Also,

1 nm = 10⁻⁹ m

1 µm = 10⁻⁶ m

So,

1 nm = 10⁻³ nm

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<u>Distance between slits ≅ 2.2 µm</u>

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Because mass and distance determine gravity, so the more mass you have, the more gravity.
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