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Leona [35]
3 years ago
14

A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont

al and has a tension of 4 N. If you move the end of the rope back and forth, you produce a transverse wave in the rope with a wave speed of 2 m/s. If you double the amount of tension you exert on the rope, what is the wave speed?
Physics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

v' = 2.83 m/s

Explanation:

Velocity of wave in stretched string is given by the formula

v = \sqrt{\frac{T}{\mu}}

here we know that

T = 4 N

also we know that linear mass density is given as

\mu = 1 kg/m

so we have

v = \sqrt{\frac{4}{1}} = 2 m/s

now the tension in the string is double

so the velocity is given as

v' = \sqrt{\frac{8}{1}} = 2\sqrt2 m/s

v' = 2.83 m/s

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