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vekshin1
3 years ago
10

In an aqueous solution containing sodium bicarbonate, aniline reacts quickly with bromine to give 2,4,6-tribromoaniline. nitrati

on of aniline requires very strong conditions, however, and the yields (mostly m-nitroaniline) are poor.

Chemistry
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:-

In bromination of aniline, due to the strongly activating NH2 group 2,4,6-tribromoaniline is formed.

In nitration of aniline the reagent used is concentrated nitric acid. Nitric acid reacts with aniline Nitrogen and protonates it. Due to NH3+ group formation, the benzene ring becomes strongly deactive in the ortho and para positions.

Hence the yields towards nitro nucleophile is poor.

The meta position being more electron rich than ortho or para due to the strongly deactivating group hence yields m-nitroaniline.

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4 years ago
In an experiment, students were given an unknown mineral. The unknown mineral was placed in 150 ml of water. Once in the water,
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Answer:

<h2>15 g/mL</h2>

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density =  \frac{mass}{volume}  \\

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5 0
3 years ago
12. A helium-filled weather balloon has a volume of 2.4 x 102 L at 99 kPa pressure and a
Luba_88 [7]

Answer:

The answer to your question is 8.74 g of He

Explanation:

Data

V = 2.4 x 10² L

P = 99 kPa

T = 0°C

mass = ?

Process

1.- Convert kPa to atm

P = 99 kPa = 99000 Pa

                   1 atm --------------- 101325 Pa

                    x       ---------------   99000 Pa

                   x = (99000 x 1) / 101325

                   x = 0.977 atm

2.- Convert temperature to °K

°K = 273 + 0

°K = 273

3.- Substitution

      PV = nRT

- Solve for n

      n = PV / RT

      n = (0.977)(2.4 x 10²) / (0.082)(273)

      n = 24.48 / 22.386

      n = 1.093 moles

4.- Calculate the grams of He

          8 g -------------------- 1 mol

           x    -------------------- 1.093 moles

           x = (1.093 x 8) / 1

           x = 8.74 g                      

6 0
4 years ago
Read 2 more answers
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