Answer:
B = CHCl2 + Cl2 --> CHCl3 + Cl
Explanation:
Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.
Free radical chlorination is divided into 3 steps which are:
The initiation step
The propagation step
The termination step
So in reference to the question, propagation step involves two steps.
The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.
The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.
You would find in the attachment the 2 step mechanism.
Answer:
Group B is the control group
Explanation:
In an experiment, a control group is the standard to which comparisons are made in an experiment.
<span>Acetone has a density of 784 kg/mÂł (this you can look up).
This equals 784.000 g/mÂł (kilo means 1000).
Which can be converted to 0.784 g/cm3 (1 m3 is 1.000.000 cm3).
A cm3 is exactly 1 ml. So 0.784 g/cm3 = 0.784 g/ml.
We have 6.68 gram of acetone. 6.68 g / 0.784 g/ml = 8.52 ml.
So the volume of 6.68 grams of acetone is 8.52 ml.</span>
The formula of this ion is CrO42– . The correct option among all the options that are given in the question is the third option or the last option. The other choices are incorrect and can be easily negated. I hope that this is the answer that you were looking for and the answer has come to your desired help.