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3 years ago

7

PLEASE HURRY! What is the relationship between distance and magnetic attraction? Give me some examples please. Pictures needed.

I will give brainliest if all are included in the answer.

1 answer:

Sholpan [36]3 years ago

6 0

Magnetism is inversely proportional to distance
this means that if distance increases magnetic attraction force decreases

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HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED

kramer

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

5 0

3 years ago

How will you prepare carbon dioxide gas on industrial scale? explain with chemical equation

r-ruslan [8.4K]

Answer:

Explanation:

https://www.bbc.co.uk/bitesize/guides/zxgkp39/revision/3

Hope it helps

3 0

3 years ago

What part of an atom is involved in a chemical reaction?

Katyanochek1 [597]

Answer:

The answer is supposed to be "Electron cloud" or "Electon".

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4 years ago

Why is carbon dioxide called a gas and not vapour?

Afina-wow [57]

Explanation:

CO2 is called as gas because it exist in single thermodynamics state i.e CO exist in gases state only at room temperature.

5 0

3 years ago

Calculate the pH of a solution that is 0.235M benzoic acid and 0.130M sodium benzoate, a salt whose anion is the conjugate base

lesantik [10]

Hello!

We have the following data:

ps: we apply Ka in benzoic acid to the solution.

[acid] = 0.235 M (mol/L)

[salt] = 0.130 M (mol/L)

pKa (acetic acid buffer) =?

pH of a buffer =?

Let us first find pKa of benzoic acid, knowing that Ka (benzoic acid) = $6.20*10^{-5}$

So:

$pKa = - log\:(Ka)$

$pKa = - log\:(6.20*10^{-5})$

$pKa = 5 - log\:6.20$

$pKa = 5 - 0.79$

$\boxed{pKa = 4.21}$

Now, using the abovementioned data for the pH formula of a buffer solution or (Henderson-Hasselbalch equation), we have:

$pH = pKa + log\:\dfrac{[salt]}{[acid]}$

$pH = 4.21 + log\:\dfrac{0.130}{0.235}$

$pH = 4.21 + log\:0.55$

$pH = 4.21 + (-0.26)$

$pH = 4.21 - 0.26$

$\boxed{\boxed{pH = 3.95}}\end{array}}\qquad\checkmark$

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR! =)

8 0

3 years ago