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jeka94
3 years ago
11

(copied from last question and fixed) (there's three question so triple points)

Chemistry
1 answer:
hammer [34]3 years ago
7 0

Question 1: A

Question 2: B

Question 3: B

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Do you think these fish are an example of natural selection among two populations of the same species
pshichka [43]
I don’t see any fish or anything
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2 years ago
Perform the following mathematical operation and report the answer to the appropriate number of significant figures. 5.4-4.21
konstantin123 [22]

Answer:

1.2   ( two significant digits)

Explanation:

5.4 - 4.21        answer should only have the the number of significant digits as the number in the equation with the least number of significant digits... in this case   5.4   is only two significant digits....so the answer should only have two significant digits

5.4 - 4.21 = 1.19     round to two digits = 1.2    

3 0
9 months ago
What is the difference between water and alcohol
Rudik [331]

Answer:

water is H2O having different structure than alcohol R-OH which means they have different properties too.

Explanation:

In water one oxygen atom  is covalently bound with  two hydrogen atoms while alcohol is an organic compound  having Oh group attached to the carbon chain.

Other than liquid water can occur in solid form that is ice and in gaseous form that is vapors too while alcohol only present in liquid form.

heat of evaporation of alcohol is lower than water means water need more heat to evaporate than alcohol that is why we can say alcohol having more cooling effect than water.

7 0
2 years ago
write the symbols for the ions that form when potassium and iodine react to form the ionic compound potassium iodide.
Bingel [31]
I believe it isK+  + I-=KI
3 0
2 years ago
Read 2 more answers
Calculate the percent ionization of nitrous acid in a solution that is 0.139 M in nitrous acid. The acid dissociation constant o
anzhelika [568]
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.

HNO2 <-> H(+) + NO2(-)

Next, create an ICE table

           HNO2   <-->  H+        NO2-
[]i        0.139M          0M       0M
Δ[]      -x                   +x         +x
[]f        0.139-x          x           x

Then, using the concentration equation, you get

4.5x10^-4 = [H+][NO2-]/[HNO2]

4.5x10^-4 = x*x / .139 - x

However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable, 

assume 0.139-x ≈ 0.139

4.5x10^-4 = x^2/0.139

Then, we solve for x by first multiplying both sides by 0.139 and then taking the square root of both sides.

We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.007M.

Then to find percent dissociation, you do final concentration/initial concentration.

0.007M/0.139M = .0503 or 

≈5.03% dissociation.
4 0
3 years ago
Read 2 more answers
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