Answer:
Salt particles will diffuse and towards where it is less that is left !!
so your answer is A !! left through diffusion !!
Explanation:
Answer:
The concentration and pKa of an acid and its conjugate base can limit the buffering capacity of a molecule.
Explanation:
A buffer is an acid and its conjugate base and the quality of it depends on its buffer capacity. This buffer capacity is the resistance to change the pH of the solution when strong acids or bases are added. The buffer capacity is related to the buffer concentration, the concentration of the acid end its conjugate base. Also, every acid has a pKa and the buffer capacity is at its maximum at the pKa value and can buffer the solution between ± 1 the pKa value.
The answer is 310 g LiNO3
:)I hope i could help!
Answer:
The correct answer is 0, 235 mol
Explanation:
We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol:
1 atm x 5, 25l = n x 0, 082 l atm / K mol x 273 K
n= 1 atm x 5, 25l /0, 082 l atm / K mol x 273 K
n= 0, 235 mol
d. Fe(s) and Al(s)
<h3>Further explanation</h3>
In the redox reaction, it is also known
Reducing agents are substances that experience oxidation
Oxidizing agents are substances that experience reduction
The metal activity series is expressed in voltaic series
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the metal located on the left can push the metal on the right in the redox reaction
The electrodes which are easier to reduce than hydrogen (H), have E cells = +
The electrodes which are easier to oxidize than hydrogen have a sign E cell = -
So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)
The metal : d. Fe(s) and Al(s)
