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natta225 [31]
3 years ago
13

How many neutrons does the isotope N-14 have?

Chemistry
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

7

Explanation:

N-14 has 7

i looked it up ye ur probably gonna get it right

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Calculate the number of grams of C2H6 in 4.6 miles of C2H6
Bezzdna [24]
M (C2H6) = n × M = 4.6 × 30 = 13.8 g.
3 0
3 years ago
The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon
xenn [34]

<u>Answer:</u> The percent composition of Fe_3O_4 in taconite is 37.6 %.

<u>Explanation:</u>

We are given:

Mass of taconite pellets = 1 ton = 907185 g      (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g    (Conversion factor:  1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of Fe_3O_4 = 231.53 g/mol

1 mole of Fe_3O_4 contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of Fe_3O_4

So, 247212 grams of iron will be produced from = \frac{231.53}{167.55}\times 247212=341611.43g of Fe_3O_4

To calculate the percentage of Fe_3O_4 in taconite, we use the equation:

\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100

Mass of taconite = 907185 g

Mass of Fe_3O_4 = 341611.43 g

Putting values in above equation, we get:

\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%

Hence, the percent composition of Fe_3O_4 in taconite is 37.6 %.

8 0
3 years ago
Ferris &amp; Mona used the ORP sensor to titrate a ferrous ammonium sulfate solution, (NH4)2Fe(SO4)2 with KMnO4 titrant.
DIA [1.3K]

Answer:

The correct option is: A. 0.168 M

Explanation:

Chemical reaction involved:

5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O

Given: <u>For MnO₄⁻ solution</u>-

Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;

<u>For Fe²⁺ solution</u>:

Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M

<u><em>To find out the concentration of Fe²⁺ solution (M₂), we use the equation:</em></u>

\frac{M_{1}\times V_{1}}{n_{1}} = \frac{M_{2}\times V_{2}}{n_{2}}

\frac{0.0250 M\times 20.2 mL}{1} = \frac{M_{2}\times 15 mL}{5}

0.505 = M_{2}\times 3

M_{2} = \frac{0.505}{3} = 0.168M

<u>Therefore, the concentration or molarity of Fe²⁺ solution: </u><u>M₂ = 0.168 M</u>

8 0
4 years ago
If mass =180kg and volume =90m3, what is the density
DaniilM [7]
To find the density you must divide the mass by the density.
180kg ÷ 90m³ = 2kg/m<span>³
The density is </span>2kg/m³
4 0
3 years ago
4 Lef's say you find a fossil in a layer of shale. How might you determine the age of the shale?
VLD [36.1K]

Answer:

why u blocked i fought we were mates

Explanation:

8 0
3 years ago
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