Answer: The change in entropy change when 207 g of toluene boils at 
is 223 
.
Explanation:
It is given that mass of toulene is 207 g and its molar mass is 92.14 g/mol. So, its moles will be calculated as follows.
No. of moles = 
= 
= 2.25 moles
As we are given that heat of vaporization for 1 mol is 38.1 kJ/mol. So, heat of vaporization for 2.25 moles will be calculated as follows.
= 85.725 KJ
Now, we know that the relation between enthalpy change and entropy change is as follows.
= 
= 0.223 
or, = 223 (as 1 kJ = 1000 J)
Thus, we can conclude that the change in entropy change when 207 g of toluene boils at is 223 .
Answer:
Bromobenzoic acid
Explanation:
COOH has higher priority than Br, so the parent name is benzoic acid.
The COOH group is automatically on C1 of the ring, and the other aromatic carbons are numbered sequentially around the ring.
The name of the substituent is joined to that of the parent, and the locant is attached to that with a hyphen.
The generic IUPAC name is bromobenzoic acid.
There are three isomers of benzoic acid — 2-bromobenzoic acid, 3-bromobenzoic acid, and 4-bromobenzoic acid — so you must always specify which one you mean.
You need to find the mole of glucose by using the formula n = m/Mr. Once you have found the mole you need to follow the stoichiometric process by unknown/known using the co-efficients. Then you need to multiple your answer by the known mole of glucose whoch you have previously calculated. After that you should get the mole of oxygen then you just need to transpose the equation to get m = n×Mr, substitute ypur answers in, remebering you can find your Mr via the period table, you have your answer
Answer:
Fusion powers the Sun and stars as hydrogen atoms fuse together to form helium, and matter is converted into energy. Hydrogen, heated to very high temperatures changes from a gas to a plasma in which the negatively-charged electrons are separated from the positively-charged atomic nuclei (ions).
I hope it's helpful!
