M (C2H6) = n × M = 4.6 × 30 = 13.8 g.
<u>Answer:</u> The percent composition of
in taconite is 37.6 %.
<u>Explanation:</u>
We are given:
Mass of taconite pellets = 1 ton = 907185 g (Conversion factor: 1 ton = 907185 g)
Mass of iron produced = 545 lb = 247212 g (Conversion factor: 1 lb = 453.6 g )
We know that:
Molar mass of iron = 55.85 g/mol
Molar mass of
= 231.53 g/mol
1 mole of
contains 3 moles of iron atom and 4 moles of oxygen atom
(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of 
So, 247212 grams of iron will be produced from =
of 
To calculate the percentage of
in taconite, we use the equation:

Mass of taconite = 907185 g
Mass of
= 341611.43 g
Putting values in above equation, we get:

Hence, the percent composition of
in taconite is 37.6 %.
Answer:
The correct option is: A. 0.168 M
Explanation:
Chemical reaction involved:
5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) → 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O
Given: <u>For MnO₄⁻ solution</u>-
Number of moles: n₁ = 1, Volume: V₁ = 20.2 mL, Concentration: M₁ = 0.0250 M;
<u>For Fe²⁺ solution</u>:
Number of moles: n₂ = 5, Volume: V₂ = 15 mL, Concentration: M₂ = ?M
<u><em>To find out the concentration of Fe²⁺ solution (M₂), we use the equation:</em></u>




<u>Therefore, the concentration or molarity of Fe²⁺ solution: </u><u>M₂ = 0.168 M</u>
To find the density you must divide the mass by the density.
180kg ÷ 90m³ = 2kg/m<span>³
The density is </span>2kg/m³
Answer:
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Explanation: