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Westkost [7]
3 years ago
7

A box of mass 115 kg sits on an inclined surface with an angle of 59º. What

Physics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

966 N

Explanation:

The component of the weight along the direction perpendicular to the plane is:

mg cos \theta

where

m is the mass of the box, g the acceleration of gravity, \theta the angle of the inclined plane.

Similarly, the component of the weight of the box along the surface is

mg sin \theta

acting down along the incline.

Here we have:

m = 115 kg

g = 9.8 m/s^2

\theta=59^{\circ}

Substitting in the last equation, we find the component of the weight of the box along the surface:

mg sin \theta = (115)(9.8)(sin 59)=966 N

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