Answer:
D. Calculate the area under the graph.
Explanation:
The distance made during a particular period of time is calculated as (distance in m) = (velocity in m/s) * (time in s)
You can think of such a calculation as determining the area of a rectangle whose sides are velocity and time period. If you make the time period very very small, the rectangle will become a narrow "bar" - a bar with height determined by the average velocity during that corresponding short period of time. The area is, again, the distance made during that time. Now, you can cover the entire area under the curve using such narrow bars. Their areas adds up, approximately, to the total distance made over the entire span of motion. From this you can already see why the answer D is the correct one.
Going even further, one can make the rectangular bars arbitrarily narrow and cover the area under the curve with more and more of these. In fact, in the limit, this is something called a Riemann sum and leads to the definition of the Riemann integral. Using calculus, the area under a curve (hence the distance in this case) can be calculated precisely, under certain existence criteria.
Answer:
Explanation:
Given that
Number of particle =N
Equilibrium temperature= T
Side of cube = L
Gravitational acceleration =g
The kinetic energy of an atom given as
Where
Equilibrium temperature= T
Boltzmann constant =K
K =1.380649×10−23 J/K
Answer:
Explanation:
Volume of the insulating shell is,
Charge density of the shell is,
Here, 
B)
The electric field is 
For 0 <r<R the electric field is zero, because the electric field inside the conductor is zero.
C)
For R <r <2R According to gauss law
substitute 
D)
The net charge enclosed for each r in this range is positive and the electric field is outward
E)
For r>2R
Charge enclosed is zero, so electric field is zero
Answer:
Nuclear fusion produces elements that are heavier than helium.
Explanation:
In the veeeery distant future, our sun will transform into a red giant, and in the even more distant future, it will become a white dwarf.
