Answer:
14.112 mV
Explanation:
L = 16 m, v = 21 m/s, B = 42 μ T = 42 x 10^-6 T
The formula for the induced emf is given by
e = B x v x L
e = 42 x 10^-6 x 21 x 16 = 14.112 x 10^-3 V = 14.112 mV
Thus, the induce emf is 14.112 mV.
Answer:
9.6 m
Explanation:
This is a case of motion under variable acceleration . So no law of motion formula will be applicable here. We shall have to integrate the given equation .
a = 3.6 t + 5.6
d²x / dt² = 3.6 t + 5.6
Integrating on both sides
dx /dt = 3.6 t² / 2 + 5.6 t + c
where c is a constant.
dx /dt = 1.8 t² + 5.6 t + c
when t = 0 , velocity dx /dt is zero
Putting these values in the equation above
0 = 0 +0 + c
c = 0
dx /dt = 1.8 t² + 5.6 t
Again integrating on both sides
x = 1.8 t³ / 3 + 5.6 x t² /2 + c₁
x = 0.6 t³ + 2.8 t² + c₁
when t =0, x = 0
c₁ = 0
x = 0.6 t³ + 2.8 t²
when t = 1.6
x = .6 x 1.6³ + 2.8 x 1.6²
= 2.4576 + 7.168
= 9.6256
9.6 m
The kinetic energy will rise once the body comes back down. As it goes up, the potential energy increases while the kinetic energy decreases. Once the body is at its maximum height, the potential energy is at it’s highest. When it starts falling, it will gain kinetic energy and lose potential energy.
Answer:
(C) 16
Explanation:
Given:
The amplitude of first wave (s₁) = 20 mm
The amplitude of second wave (s₂) = 5 mm
Intensity of first wave = Iₓ
Intensity of second wave = 
The intensity associated with a wave depends on the amplitude of the wave.
The intensity (I) is directly proportional to the square of the amplitude (s) of the wave and is expressed as:
Now, the intensities of the two waves are given as:
Dividing both the intensities, we get:
Therefore, the option (C) is correct.
