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N76 [4]
3 years ago
6

For a projectile launched horizontally, which of the following best describes the downward component of a projectile's velocity?

Assume air resistance is negligible.A. The downward component of the projectile's velocity is zero.B. The downward component of the projectile's velocity remains a nonzero constant.C. The downward component of the projectile's velocity continually increases.D. The downward component of the projectile's velocity continually decreases.E. The downward component of the projectile's velocity initially decreases and then increases.
Physics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

C. The downward component of the projectile's velocity continually increases

Explanation:

The motion of a projectile consists of two independent motions:  

- A uniform motion (with constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (equal to the acceleration of gravity) in the downward direction  

Here we want to study the downward component of the projectile's velocity. Since the vertical motion is a uniformly accelerated motion, the vertical velocity is given by:

v=u+at

where

u = 0 is the initial vertical velocity (zero since the projectile is fired horizontally)

a=g=9.8 m/s^2 downward is the acceleration of gravity

t is the time

So the equation becomes

v=gt

This means that

C. The downward component of the projectile's velocity continually increases

Because every second, it increases by 9.8 m/s in the downward direction.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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Answer:

The BMX lands 5.4 m from the end of the ramp.

Explanation:

Hi there!

The position of the BMX is given by the position vector "r":

r = (x0 + v0 · t · cos α, y0 + v0 · t · sin α + 1/2 · g · t²)

Where:

r = position vector at time t

x0 = initial horizontal position

v0 = initial velocity

α = jumping angle

y0 = initial vertical position

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive)

Please, see the attached graphic for a better understanding of the situation. At final time, when the bicycle reaches the ground, the vector position will be "r final" (see figure). The y-component of the vector "r final" is - 2.4 m (placing the origin of the frame of reference at the jumping point). With that information, we can use the equation of the y-component of the vector "r" (see above) to calculate the time of flight. With that time, we can then obtain the x-component (rx in the figure) of the vector "r final". Then:

y = y0 + v0 · t · sin α + 1/2 · g · t²

-2.4 m = 0 m + 5.9 m/s · t · sin 40° - 1/2 · 9.8 m/s² · t²

0 = -4.9 m/s² · t² + 5.9 m/s · t · sin 40° + 2.4 m

Solving the quadratic equation:

t = 1.2 s

Now, we can calculate the x-component of the vector "r final" that is the horizontal distance traveled by the bicycle:

x = x0 + v0 · t · cos α

x = 0 m + 5.9 m/s · 1.2 s · cos 40°

x = 5.4 m

The BMX lands 5.4 m from the end of the ramp.

Have a nice day!

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Forces can act on an object in the same direction or in opposite. how does each situation affect the motion of the object?
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Hi pupil here's your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



Action and Reaction do not act on the same body !! If they acted on the same body, the resultant force will be zero and their could be never accelerated motion.

If both the forces acted on the same body, then if they are equal to opposite direction the object will remain stationary. If on of the forces is greater than other the object will move in the direction of greater force.

If both acted in the same direction there would be an accelrated motion.




⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅





Hope this helps . . . . .
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