Question

Given f(x) = x2-2 and g(x) = sqrt x find f(g(2))

Answer 1

Answer:

$\boxed{\boxed{f\bigg(g(2)\bigg)=0}}$

Step-by-step explanation:

$f(x)=x^2-2,\ g(x)=\sqrt{x}\\\\Domain:\\D_f:x\in\mathbb{R}\\\\D_g:x\geq0\\\\f(g(x))=\left(\sqrt{x}\right)^2-2=x-2$

$Used:\\\\(\sqrt{a})^2=a$

$f(g(2)):\\\text{Put x = 2 to the equation of the function:}\\\\f(g(2))=2-2=0$

Answer 2

Answer:

The value of $f(g(2))$ is 0

Step-by-step explanation:

Given:

$f(x) = x^2-2$ and $g(x) = \sqrt{x}$

we have to find the $f(g(2))$.

first find $g(2)$

Put x =2 in g(x) we have;

$g(2) = \sqrt{2}$

Now;

$f(g(2))=f(\sqrt{2})=(\sqrt{2})^2-2 = 2-2 = 0$

Therefore, the value of $f(g(2))$ is 0