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NARA [144]
3 years ago
13

The world’s population is expected to grow at a rate of 1.3% per year until at least the year 2020. In 1994 the total population

of the world was about 5,642,000,000 people. Use the formula Pn=P₀e^in to predict the world’s population Pn , n years after 1994, with P₀ equal to the population in 1994 and i equal to the expected growth rate. What is the world’s predicted population in the year 2020, rounded to the nearest million?
( the ₀ is supposed to be a little zero)
Mathematics
1 answer:
Flauer [41]3 years ago
7 0

Answer:

Therefore, the the world's predicted population in the year 2020 is 7,911×10^6 people.

Step-by-step explanation:

Given:  

P₀ = 5,642×10^6 people,  

i = 1.3% = 0.013 per year,  

n = 2020 - 1994 = 26 years,  

We get:  

Pn = P₀ e^(i.n)  

. . .= 5,642×10^6×e^(0.013×26)  

. . .= 7,911×10^6 people

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Answer:

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3 years ago
Luke runs a farm stand that sells strawberries and blueberries. Each pound of
koban [17]
Answer:
He would make $36 for 12 pounds of strawberries
He would make $196 for 49 pounds of blueberries

He would make 3S if he sold S pounds of strawberries
He would make 4B if he sold B pounds of blueberries

Working:
We know that strawberries are $3/pound so $3 x 12pounds = $36
We know that blueberries are $4/pound so $4 x 49pounds = $196

The letters represent the amount of pounds of fruit being bought so the calculation for that is ($ x pounds) so you would write this but without assigning a numerical value to the amount. So if the strawberries are $3/pound and Luke sold ‘s’ pounds then it would be 3S (or 3xS but that is already assumed). The same goes for the blueberries. We know that they are $4/pound so it would be 4B.

Sorry if this doesn’t make any sense but I hope this helped

4 0
3 years ago
In the rhombus m<1 = 160°. what are m<2 and m<3? ​
ehidna [41]
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5 0
3 years ago
Read 2 more answers
How can i calculate the growth rate of the values below
Grace [21]

Answer:

  12%

Step-by-step explanation:

The equation for the growth is ...

  f(t) = (initial value)×(growth multiplier per period)^(number of periods)

where the growth multiplier is often expressed as a percentage added to 1:

  multiplier = 1+r

  growth rate = r

__

This equation has two unknowns:

  • initial value
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In order to find these, you can make use of two of the supplied data points. I like to choose the ones that are farthest apart, as they tend to average out any errors due to rounding.

Clearly, the table tells you the initial value is 210. If you don't believe, you can put the numbers in the equation to see that:

  f(0) = (initial value)×(growth multiplier)^0

  210 = (initial value)×1

  (initial value) = 210

__

Using the last data point, we get ...

  f(7) = 210×(growth multiplier)^7

  464 = 210×(growth multiplier)^7 . . . . . . . . . fill in table value

  2.209524 = (growth multiplier)^7 . . . . . . .  divide by 210

You can solve this a couple of ways. My calculator is able to take the 7th root, so I can use it to find ...

  \sqrt[7]{2.209524}=\text{(growth multiplier)}\\1.119916\approx \text{(growth multiplier)}

Alternatively, you can use the 1/7 power:

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Another way to solve this is to use logarithms:

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So, our growth multiplier is ...

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The rate of growth is about 12% in each period.

_____

Collapsing all of that to a single calculation:

  growth rate = (464/210)^(1/(7-0)) -1 ≈ 12.0%

8 0
3 years ago
How can polygons be considered a subcategory of two-dimensional figures?
Sonbull [250]
I say subcategory would be a good answer
6 0
3 years ago
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