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vovangra [49]
3 years ago
6

Convert 302 K into C

Chemistry
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

302°K = 28.85°C

Explanation:

Formula: °K - 273.15 = °C

0°C is equal to roughly 273°K

Simply plug it into the formula to find your temperature:

302°K - 273.15 = °C

°C = 28.85

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5 0
3 years ago
Read 2 more answers
A mixture containing nitrogen and hydrogen weighs 3.48 g and occupies a volume of 7.47 L at 296 K and 1.02 atm. Calculate the ma
Sonbull [250]

Answer:

there is 2% of hydrogen and 98% of nitrogen (mass percent)

Explanation:

assuming ideal gas behaviour

P*V=n*R*T

n= P*V/(R*T)

where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)

thus

n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles

since the number of moles is related with the mass m through the molecular weight M

n=m/M

thus denoting 1 as hydrogen and 2 as nitrogen

m₁+m₂ = mt (total mass)

m₁/M₁+m₂/M₂ = n

dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁

w₁/M₁+w₂/M₂ = n/mt

w₁/M₁+(1-w₁) /M₂ = n/mt

w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂)

replacing values

w₁=  (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)

and w₂= 1-w₁= 0.98 (98%)

thus there is 2% of hydrogen and 98% of nitrogen

4 0
3 years ago
If you are asked to compare matter in solid, liquid, and gaseous states, which statement best defines a gas?
Natali [406]
<span>The answer is A. Gases are spread throughout the air and not packed tightly together. therefore the molecules move quickly and are least densely packaged. They have the highest energy because they also have the highest molecular motion. </span>
5 0
3 years ago
Read 2 more answers
"what is the mole fraction of solute in a 3.87 m aqueous solution?"
sattari [20]

The mole fraction of solute in a 3.87 m aqueous solution is 0.0697

<h3> calculation</h3>

molality = moles of the solute/Kg of the solvent

3.87 m dissolve in 1 Kg of water= 1000g

find the moles of water= mass/molar mass

that is 1000 g/ 18 g/mol= 55.56 moles

mole of solute = 3.87 moles

mole fraction is = moles of solute/moles of solvent

that is 3.87/ 55.56 = 0.0697

5 0
3 years ago
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How many moles of hydrogen are required to make 32 moles of water?
NNADVOKAT [17]
You multiply 32 by 2, since there are two hydrogens in every water molecule.
7 0
4 years ago
Read 2 more answers
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