Question

I need HELP!!

Answer 1

Answer: Hit not Hard it is Hoc2 (Hydgergon Perocide)

Explanation: Water plus co(g)= HoC2

Answer 2

Answer : The enthalpy change for the reaction is, 269 kJ/mol

Explanation :

The given chemical reaction is:

$H_2+CO_2\rightarrow CO+H_2O$

As we know that:

The enthalpy change of reaction = E(bonds broken) - E(bonds formed)

$\Delta H=[(B.E_{H-H})+(2\times B.E_{C=O})]-[(2\times B.E_{O-H})+(1\times B.E_{C\equiv C})]$

Given:

$\Delta H$ = enthalpy change

$B.E_{H-H}$ = 436 kJ/mol

$B.E_{O-H}$ = 463 kJ/mol

$B.E_{C=O}$ = 799 kJ/mol

$B.E_{C\equiv C}$  = 839 kJ/mol

Now put all the given values in the above expression, we get:

$\Delta H=[(436kJ/mol)+(2\times 799kJ/mol)]-[(2\times 463kJ/mol)+(1\times 839kJ/mol)]$

$\Delta H=269kJ/mol$

Therefore, the enthalpy change for the reaction is, 269 kJ/mol