One mole of C= 12 grams
two moles of O =32
so one mole of CO^2 is44 grams
.1 moles or 1/10 moles of 44 grams is 4.4 grams
Answer:
The mole fraction of ethanol is 0.6. A 10 mL volumetric pipette must be used for to measure the 10 mL of ethanol. The vessel should be clean and purged.
Explanation:
For calculating mole fraction of ethanol, the amount of moles ethanol must be calculated. Using ethanol density (0.778 g/mL), 10 mL of ethanol equals to 7.89 g of ethanol and in turn 0.17 moles of ethanol. The same way for calculate the amount of water moles (ethanol density=0.997 g/mL). 2 mL of water correspond to 0.11. The total moles are: 0.17+0.11=0.28. Mole fraction alcohol is: 0.17/0.28=0.6
Answer:
Part B : Hg
Part C : Ag
Explanation:
When we added ammonium hydroxide to the solid remains after addition hot water , AgCl dissolve due to the formation of soluble complex [Ag(NH3)2]+ and Hg2Cl2 gives black precipitate with ammonium hydroxide due to formation of elemental mercury.
Black precipitate is not formed upon addition of amonium hydroxide to the precipitate remains after addition of hot water, so Hg22+ is shown not to be present.
The precepite remains after addition of hot water is dissolved by the addition of ammonium hydroxide, so Ag+ may be present. The presence of Ag+ is not confiremed by K2CrO4 test.
