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Oliga [24]
3 years ago
5

Need help with this please thanks

Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer: 1. 2H_2+O_2\rightarrow 2H_2O

2. P_4+3O_2\rightarrow 2P_2O_3

3. N_2+3H_2\rightarrow 2NH_3

4. 2K+Cl_2\rightarrow 2KCl

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The given equations are balanced as:

1. 2H_2+O_2\rightarrow 2H_2O

2. P_4+3O_2\rightarrow 2P_2O_3

3. N_2+3H_2\rightarrow 2NH_3

4. 2K+Cl_2\rightarrow 2KCl

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How many liters of o2 do you have if you have 5.8 moles of o2
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Answer:

130 Liters

Explanation:

if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)

3 0
3 years ago
A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 23.0 mL of
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NaOH reacts with CH3COOH in 1:1 molar ratio to produce CH3COONa 

NaOH + CH3COOH → CH3COONa + H2O 

Mol CH3COOH in 52.0mL of 0.35M solution = 52.0/1000*0.35 = 0.0182 mol CH3COOH 

Mol NaOH in 19.0mL of 0.40M solution = 19.0/1000*0.40 = 0.0076 mol NaOH 

These will react to produce 0.0076 mol CH3COONa and there will be 0.0182 - 0.0076 = 0.0106 mol CH3COOH remaining in solution unreacted . Total volume of solution = 52.0+19.0 = 71mL or 0.071L 

Molarity of CH3COOH = 0.0106/0.071 = 0.1493M 

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pKa acetic acid = - log Ka = -log 1.8*10^-5 = 4.74. 

pH using Henderson - Hasselbalch equation: 

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pH = 4.74 + log 0.717 

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7 0
3 years ago
The periodic table is based on an element's
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The answer will be B.
4 0
3 years ago
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How many atoms are in 4.93 moles hcl?
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1 mole ------------- 6.02x10²³ atoms
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4.93 x ( 6.02x10²³) / 1 = 

=> 2.96x10²⁴ atoms
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As this is a neutral isotope, that means that is going to have the same number of protons and electrons, that is 29.

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