CR < CY < CB
<h3>Which factors affect the critical angle for a given pair of media?</h3>
The factors which affect the critical angle are
(a) The colour (or wavelength) of light
(b) The temperature
(i) Effect of colour of light: The critical angle for a pair of media is less for the violet light and more for the red light. Thus the critical angle increases with the increase in wavelength of light.
(ii) Effect of temperature: The critical angle increases with increase in temperature because on increasing temperature of medium, its refractive index decreases.
According to the question,
μ 1 sinCR =1
μ 2 sinCY =1
μ 3 sinCB =1
μ 1 > μ 2 and μ 2 > μ 3
⟹μ 1 > μ 2 > μ 3
CR < CY < CB
Thus,
The critical angle increases with the increase in wavelength of light.
Learn more about wavelength of light here:
brainly.com/question/27557868
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I hope this helps. it was right when i took the test.
Explanation:
Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)
initial speed of the stuntman is given as

angle of inclination is given as

now the components of the velocity is given as


here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.
So the displacement in vertical direction is given as



by solving above equation we have

Now in the above interval of time the horizontal distance moved by it is given by


since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.
Answer:
Explanation:
Capacitor of 0.75μF, charged to 70V and connect in series with 55Ω and 140 Ω to discharge.
Energy dissipates in 55Ω resistor is given by V²/R
Since the 55ohms and 140ohms l discharge the capacitor fully, the voltage will be zero volts and this voltage will be shared by the resistor in ratio.
So for 55ohms, using voltage divider rule
V=R1/(R1+R2) ×Vt
V=55/(55+140) ×70
V=19.74Volts is across the 55ohms resistor.
Then, energy loss will be
E=V²/R
E=19.74²/55
E=7.09J
7.09J of heat is dissipated by the 55ohms resistor