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Llana [10]
3 years ago
6

$4,000 for 5 years at 6% simple interest rate. How much interest is that

Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0
Easy 4000 times 0.6 times 5 = 1200
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What two ratios are equivalent too 27/60
kati45 [8]

Answer:

54/120 or 108/240

Step-by-step explanation:


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Could someone help me with number 6 ? The directions say what are the variables? which I know the variables are the height and t
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As the time go the grass height go through increasing and decreasing
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According to Statcast, the average left field home run travels 378 feet and reaches a maximum height of 81 feet. Assuming the ba
kogti [31]

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H = V0y t - 1/2 g t^2     equation for vertical height of object with initial speed     (V0y = V0 sin theta)

If H is to be considered an absolute value from t = 0

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8 0
3 years ago
Please help it is math related
soldi70 [24.7K]

Answer:

The slope is 3/8!

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3x-8y=-20

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the fraction is now positive because the numerator and the denominator are both negative so they are changed into positive.

Hope This Helps!

4 0
3 years ago
How many possible committees of 4 people can be chosen from 15 men and 20 women so that at least two women should be on each com
Mnenie [13.5K]

<span>If there has to be 2 men and 2 women, we know that we must take a group of 2 men out of the group of 15 men and a group of 2 women out of the group of 20 women. Therefore, we have:

(15 choose 2) x (20 choose 2)


(15 choose 2) = 105

(20 choose 2) = 190

190*105 = 19950

Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>

 

<span>If there has to be 1 man and 3 women, we know that we must take a group of 1 man out of the group of 15 men and a group of 3 women out of the group of 20 women. Therefore, we have:

(15 choose 1) x (20 choose 3)


(15 choose 1) = 15

(20 choose 3) = 1140

15*1140 = 17100

Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>

 

<span>We now find the total outcomes of having a group with 4 women.

We know this is the same as saying (20 choose 4) = 4845</span>

Therefore, there are 4845 ways to have a group of 4 with 4 women.

 

We now add the outcomes of 2 women, 3 women, and 4 women and get the total ways that a committee can have at least 2 women.

 

19950 + 17100 + 4845 = 41895 ways that there will be at least 2 women in the committee


5 0
3 years ago
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