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nlexa [21]
3 years ago
6

For the product of the reaction below, which proton is removed irreversibly by NaNH2 base, thus preventing any isomerization of

the alkyne bond in the product?

Chemistry
1 answer:
Serggg [28]3 years ago
7 0

Answer:

The Highly acidic proton joined to one of the carbon in the ALKYNE bond.

(Kindly Check the attachment for the drawing because the solution will need us to draw).

Explanation:

So, let us start by defining some major key terms in this particular Question given above;

(1). ISOMERIZATION: isomerization can simply be defined as the kind is of chemical rearrangement whichay lead to the breaking and the formation of new bonds.

(2). NaNH2 BASE: Sodium amide is a Chemical compound which has a Molar mass of 39.01 g/mol and Heat capacity (C) of 66.15 J/mol K. It is also known as sodamide. It is a good nucleophile.

(3). ALKYNE BOND: it is a C-C joined together by three bonds.

The chemical reaction given in the Question is given in the attachment too.

Therefore, The Highly acidic proton joined to one of the carbon in the ALKYNE bond  is removed irreversibly by NaNH2 base.

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3 years ago
Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.
denpristay [2]

<u>Answer:</u>

<u>For a:</u> The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

<u>For b:</u> The mass of methane gas produced will be 10.384 g.

<u>Explanation:</u>

For the given chemical reaction:

2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ

  • <u>For a:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = \frac{252.8}{2}\times 0.749=94.6736kJ

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

  • <u>For b:</u>

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = \frac{2}{252.8}\times 82.1=0.649mol of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g

Hence, the mass of methane gas produced will be 10.384 g.

7 0
3 years ago
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