For the product of the reaction below, which proton is removed irreversibly by NaNH2 base, thus preventing any isomerization of
the alkyne bond in the product?
1 answer:
Answer:
The Highly acidic proton joined to one of the carbon in the ALKYNE bond.
(Kindly Check the attachment for the drawing because the solution will need us to draw).
Explanation:
So, let us start by defining some major key terms in this particular Question given above;
(1). ISOMERIZATION: isomerization can simply be defined as the kind is of chemical rearrangement whichay lead to the breaking and the formation of new bonds.
(2). NaNH2 BASE: Sodium amide is a Chemical compound which has a Molar mass of 39.01 g/mol and Heat capacity (C) of 66.15 J/mol K. It is also known as sodamide. It is a good nucleophile.
(3). ALKYNE BOND: it is a C-C joined together by three bonds.
The chemical reaction given in the Question is given in the attachment too.
Therefore, The Highly acidic proton joined to one of the carbon in the ALKYNE bond is removed irreversibly by NaNH2 base.
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Answer:
Such molecule must have molecular formula of C15N3H15
Explanation:
Mass of carbon in such molecule
The atomic mass of carbon is 12.01 g/mol, so in 182.28 g of carbon there is 15.18 mols of carbon.
Mass of Nitrogen in such molecule
The atomic mass of nitrogen is 14.01 g/mol, so in 42.53g of nitrogen there is 3.04 mols of nitrogen.
Mass of Hydrogen in such molecule
The atomic mass of Hydrogen is 1.00 g/mol, so in 15.19 g of Hydrogen there is 15.19 mols of Hydrogen.
Such molecule must have molecular formula of C15N3H15
The limiting reagent will be Al
<h3>What are limiting reagents?</h3>They are reagents that limit the quantity of products that are formed in reactions.
From the equation of the reaction:
The mole ratio of Al to O2 is 4:3.
With 2 moles of Al and 2 moles of O2, Al becomes limiting while O2 is in excess.
With 2 moles of O2, the amount of Al required should be:
2 x 4/3 = 2.67 moles.
With 2 moles of Al, the amount of O2 required should be:
2 x 3/4 = 1.5 moles
Thus, O2 is in excess by 0.5 moles.
More on limiting reagents can be found here: brainly.com/question/11848702
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