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Pani-rosa [81]
3 years ago
9

An aqueous solution has a mass of 490 grams containing 8.5 × 10-3 gram of calcium ions. The concentration of calcium ions in thi

s solution is
Chemistry
1 answer:
Arada [10]3 years ago
5 0
The concentration may be expressed as % m/m, this is the mass of ions in 100 mass units of solution, whose formula is:

% m/m = [mass of ions / mass of solution]*100

Then,

%m/m = [8.5*10^ -3 grams of calcium ions] / [490 grams of solution] * 100 =

% m/m = 1.74 * 10^ -5 %

Answer: 1.74 * 10 ^ -5 % 
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An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with
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Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

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To determine the molar mass;

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