How many total atoms are in 0.830 g of p2o5?

Chemistry

1 answer:

docker41 [41]2 years ago

6 0

Answer:

$2.46x10^{22}atoms$

Explanation:

Hello,

In this case, we need to compute the atoms of both phosphorous and oxygen, taking into account the following mass-mole-atoms relationship:

$Molar,mass=31*2+16*5=142g/mol\\atomsP=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{2molP}{1molP_2O_5} *\frac{6.022x10^{23}atomsP}{1molP}=7.04x10^{21}atomsP\\atomsO=0.830gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5} *\frac{5molO}{1molP_2O_5} *\frac{6.022x10^{23}atomsO}{1molO}=1.76x10^{22}atomsO$

Now, by adding each result, we've got:

$atoms=1.76x10^{22}atomsP+7.04x10^{21}atomsO=2.46x10^{22}atoms$

Best regards.

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