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3 years ago

How many seconds are there in one light-year?

Chemistry

1 answer:

I am Lyosha [343]3 years ago

8 0

31,536,000 seconds because 365 days a year, 24 hours a day. Every hour is 60 minutes, and each minutes 60 seconds. So to get the answer 60 sec/min x 60 min/hr x 24 hr/day x 365 days/year = 31,536,000 seconds.

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Um.. i dont need help lol

Tasya [4]

Answer:

thats cool mate

Explanation:

hope ya have a good day, im answering just for the points tbh

7 0

3 years ago

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What total volume of ozone measured at a pressure of 24.5 mmHg and a temperature of 232 K can be destroyed when all of the chlor

ddd [48]

Answer:

$1.75272\ \text{m}^3$

Explanation:

The breakdown reaction of ozone is as follows

$CF_3Cl + UV \rightarrow CF_3 + Cl$

$Cl + O_3 \rightarrow ClO + O_2$

$O_3 + UV \rightarrow O_2 + O$

$ClO + O \rightarrow Cl + O_2$

It can be seen that 2 moles of ozone is required in the complete cycle

So for 10 cycles, 20 moles of ozone is required

m = Mass of $CF_3Cl$ = 15.5 g

M = Molar mass of $CF_3Cl$ = 104.46 g/mol

P = Pressure = 24.5 mmHg

T = Temperature = 232 K

R = Gas constant = $62.363\ \text{L mmHg/K mol}$

Number of moles is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{15.5}{104.46}\\\Rightarrow n=0.1484\ \text{moles}$

$20\ \text{moles} = 20\times 0.1484 = 2.968\ \text{moles}$

From ideal gas law we have

$PV=nRT\\\Rightarrow V=\dfrac{nRT}{P}\\\Rightarrow V=\dfrac{2.968\times 62.363\times 232}{24.5}\\\Rightarrow V=1752.72\ \text{L}=1.75272\ \text{m}^3$

For 20 cycles of the reaction the volume of the ozone is $1.75272\ \text{m}^3$ .

7 0

3 years ago

What is this thermodynamic?

VLD [36.1K]

Answer:

oh coooool

I have one Id it is on ace with maybe 5800 points

maybe this picture will help in something

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2 years ago

2. What is the current running through a toaster if the resistance is 15

pogonyaev

I’ll help you 8n a bit

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2 years ago

Which of the following is the correct isotope notation for the element above?

ozzi

7 becuse it splits in half

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3 years ago

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