Answer:
9.34 cm³
Explanation:
From the question given, we obtained the following data:
Mass of magnesium = 16.24 g
Volume of magnesium =.?
To obtain the volume of the magnesium sample, we simply apply the formula for calculating the density of samples. This is illustrated below:
Mass of magnesium = 16.24 g
Density of magnesium 1.738 g/cm³
Volume of magnesium =.?
Density = mass /volume
1.738 = 16.24/volume
Cross multiply
1.738 × volume = 16.24
Divide both side by 1.738
Volume of magnesium = 16.24/1.738
Volume of magnesium = 9.34 cm³
Therefore, the density of the magnesium sample is 9.34 cm³.
Hello!
First, we can assume the density of water to be
1 g/mL, so the volume of water would be
725 mL. The density of Acetic Acid (Pure) is
1,05 g/mL so 8 grams would represent
7,61 mLNow we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:
![[CH_3CO_2H]=\frac{8 g_{CH_3CO_2H} }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D%5Cfrac%7B8%20g_%7BCH_3CO_2H%7D%20%20%7D%7B725%20mL%20%2B%207%2C61%20mL%7D%2A%20%5Cfrac%7B1000%20mL%7D%7B1%20L%7D%2A%20%5Cfrac%7B1%20mol_%7BCH_3CO_2H%7D%20%7D%7B60%2C05%20g_%7BCH_3CO_2H%7D%20%7D)
![[CH_3CO_2H]=0,1818 M](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D0%2C1818%20M)
So, the concentration of acetic acid would be
0,1818 MHave a nice day!
Answer:
Pyridine solution has a greater concentration of hydroxide ions.
Explanation:
The pOH of the solution is defined as negative logarithm of hydroxide ion concentration in a solution.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
- Higher the value of pOH lessor will be the hydroxide ion concentration and higher the concentration of hydrogen ions in the solution .
- Lower the value of pOH higher will be the hydroxide ion concentration and lower the concentration of hydrogen ions in the solution.
1) The pOH of the methylamine = 6.8
![6.8=-\log[OH^-]](https://tex.z-dn.net/?f=6.8%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=1.5848\times 10^{-7} M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.5848%5Ctimes%2010%5E%7B-7%7D%20M)
2) The pOH of the pyridine = 6.0
![6.0=-\log[OH^-]](https://tex.z-dn.net/?f=6.0%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=0.000001 M=1.0\times 10^{-6} M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.000001%20M%3D1.0%5Ctimes%2010%5E%7B-6%7D%20M)
Pyridine solution has a greater concentration of hydroxide ions than the solution of methylamine.
Answer:
32.4 L
Explanation:
Note 1:
The Standard Temperature and Pressure (STP) is defined by IUPAC as air at 0 gradius Celcius and 1 bar.
Note 2:
The Ideal Gas Law is used for solving this problem.
......
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!