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3 years ago

What is the missing part of the chemical equation shown below? acid + base ? salt + ________

Chemistry

2 answers:

Gennadij [26K]3 years ago

5 0

Water is the answer.

lions [1.4K]3 years ago

3 0

Water
example HCl + NaOH= NaCl +H2O

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According to one acid-base theory, water can act as a base because a water molecule can

Anna11 [10]

Answer:

1) donate an H+ ion

Explanation:

option 1 is correct

3 0

2 years ago

How many mg of O2 will react with the TNT?

Tanzania [10]

TNT has the molecular formula: C7H5N3O6. And hence, when reacted in oxygen gas, you get what is known as combustion reaction. the reaction is: C7H5N3O6+O2→CO2+N2+H2O

6 0

3 years ago

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

sveta [45]

Explanation:

The given data is as follows.

$E^{o}$ = 0.483, $[Co^{3+}]$ = 0.173 M,

$[Co^{2+}]$ = 0.433 M, $[Cl^{-}]$ = 0.306 M,

$P_{Cl_{2}}$ = 9.0 atm

According to the ideal gas equation, PV = nRT

or, P = $\frac{n}{V}RT$

Also, we know that

Density = $\frac{mass}{volume}$

So, P = MRT

and, M = $\frac{P}{RT}$

= $\frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}$

= $\frac{9.0}{24.436}$

= 0.368 mol/L

Now, we will calculate the cell potential as follows.

E = $E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}$

= $0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}$

= $0.483 - 0.02955 log \frac{0.0689}{0.0162}$

= $0.483 - 0.02955 \times 0.628$

= 0.483 - 0.0185

= 0.4645 V

Thus, we can conclude that the cell potential of given cell at $25^{o}C$ is 0.4645 V.

4 0

3 years ago

Is Amplitude a measure of a waves? A. speed B. energy C. distance D. frequency

iren2701 [21]

the answer is C. Distance

hope this helps :)

5 0

3 years ago

Read 2 more answers

Bauxite is an ore that contains the element aluminum. If you obtained 108 grams of aluminum from an ore sample that initially we

Stels [109]

Answer:

53% aluminium is present.

Explanation:

Given data:

Mass of aluminium in bauxite = 108 g

Total mass of sample = 204 g

Percentage of aluminium = ?

Solution:

Formula:

Percentage = Mass of aluminium / total mass of sample× 100

Now we will put the values in formula:

Percentage = 108 g/204 × 100

Percentage = 0.53 × 100

Percentage = 53%

So in given 204 g of bauxite there is 53% aluminium is present.

8 0

3 years ago