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denis-greek [22]
3 years ago
15

What is the gravitational attraction on you due to a mountain with a mass of 100 million metric tons 1 km away ?

Physics
1 answer:
nikklg [1K]3 years ago
6 0

The magnitude of the gravitational attraction is 4\cdot 10^{-4} N.

Explanation:

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, we have

m_1 = 60 kg is my mass

The mass of the mountain is 100 million tons, and keeping in mind that

1 ton = 1000 kg

The mass of the mountain is

m_2 = 100 \cdot 10^6 tons =100 \cdot 10^6 tons \cdot (1000 kg/ton)=100\cdot 10^9 kg

The distance between me and the mountain is

r = 1 km = 1000 m

Therefore, the gravitational attraction is

F=\frac{(6.67\cdot 10^{-11})(100\cdot 10^9)(60)}{(1000)^2}=4\cdot 10^{-4} N

Learn more about gravitational force here:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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A car slams on the brakes to stop. The road pushes back up on the car with a normal force of 12,750 N and friction from the brak
ivann1987 [24]

Answer:

\displaystyle \mu_d=0.75

Explanation:

Coefficients of Friction

Objects in physical contact produce friction which usually manifests as thermal energy being dissipated in the surface where the objects are interacting. It's usually harder to start to move an object from rest, that keeps moving it at a constant speed on the same surface. That is why there are two different coefficients of friction: the static and the dynamic. As mentioned, the static coefficient \mu_s is greater than the dynamic coefficient \mu_d. The car is already moving and is attempting to stop. The coefficient of friction is defined as

\displaystyle \mu_d=\frac{F_r}{N}

Where Fr is the force of friction and N is the normal or the force the road pushes back up on the car. With the given data, we have

\displaystyle \mu_d=\frac{9,560\ N}{12,750\ N}

\displaystyle \boxed{\mu_d=0.75}

The coefficient of friction is dimensionless (doesn't have any units)

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Your fitness tracker tells you that you have delivered 124 kJ of work during your workout. The tracker also shows that you have
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To solve this problem, we must basically count the total energy lost converting all the values given in the international system.

The energy loss is given by both 124KJ and 124food heats.

Since the energy conversion we know that 1 food calories is equal to 4,184J. So:

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