Answer:
227 m/s
Explanation:
Kinetic energy formula:
- where m = mass of the object (kg)
- and v = speed of the object (m/s)
Let's find the kinetic energy of the 145-g baseball moving at 31.0 m/s.
First convert the mass to kilograms:
Plug known values into the KE formula.
Now we want to find how fast a 2.70-g ping pong ball must move in order to achieve a kinetic energy of 69.6725 J.
First convert the mass to kilograms:
Plug known values into the KE formula.
The ping-pong ball must move at a speed of 227 m/s to achieve the same kinetic energy as the baseball.
Answer:
a)43.8 m/s
b)103.54 m/s
Explanation:
Work energy theorem
Δ
Δ![E_{g}](https://tex.z-dn.net/?f=E_%7Bg%7D%20)
![E_{k2} - E_{k1}=-(E_{g2} - E_{g1})\\\\ \frac{1}{2} mv^{2}_{2}- \frac{1}{2} mv^{2}_{1}+ mgh_{2} - mgh_{1} = 0](https://tex.z-dn.net/?f=E_%7Bk2%7D%20-%20E_%7Bk1%7D%3D-%28E_%7Bg2%7D%20-%20E_%7Bg1%7D%29%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D_%7B2%7D-%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D_%7B1%7D%2B%20mgh_%7B2%7D%20-%20mgh_%7B1%7D%20%3D%200)
a) In this part v1=0 and h2=0
=0
b) in this part v2=0, h1= 0, and h2= 545m
![\frac{1}{2} v^{2}_{1}= gh_{2} \\v_{1} =\sqrt{2gh_{2}}=103.54m/s](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20v%5E%7B2%7D_%7B1%7D%3D%20gh_%7B2%7D%20%5C%5Cv_%7B1%7D%20%3D%5Csqrt%7B2gh_%7B2%7D%7D%3D103.54m%2Fs)
<h2>
Height of cliff is 66.43 meter.</h2>
Explanation:
Consider the horizontal motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 1770 m/s
Acceleration, a = 0 m/s²
Displacement, s = 6520 m
Substituting
s = ut + 0.5 at²
6520 = 1770 x t + 0.5 x 0 xt²
t = 3.68 s
Time of flight of shell = 3.68 s.
Now consider the vertical motion of shell,
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 9.81 m/s²
Time, t = 3.68 s
Substituting
s = ut + 0.5 at²
s = 0 x 3.68 + 0.5 x 9.81 x 3.68²
s = 66.43 m
Height of cliff is 66.43 meter.
Hello, there Jcparris
Your answer is going to be C. Frequency
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Answer:
Explanation:
constant speed is where the speed is the same throughout and instantaneous speed is speed given at any moment and average speed is a total distance traveled divided by the amount of time it took to travel it.