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elena-14-01-66 [18.8K]
3 years ago
9

If an astronaut throws an object in space, the object's speed will _____________. A) decrease. B) increase. C) remain constant.

D) there's not enough information to answer this question.
Physics
2 answers:
GenaCL600 [577]3 years ago
7 0

The object's speed will remain constant after the it leaves his hand.

So will HIS speed in the opposite direction.

Mazyrski [523]3 years ago
5 0

C. Remain Constant

There are no forces to act upon the object; therefore it would remain in motion at a constant speed.

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Which of the following is true about radiation from the sun?
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><span>It can travel through vacuum. 

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A bowling ball travels at 2.0 m/s. It has 16 J of kinetic energy. what Is the mass of the bowling ball in kilograms ?
zaharov [31]
Kinetic energy = 1/2 × m × v^2
16 = 1/2 × m × 2^2
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6 0
2 years ago
When an object is falling and reaches a constant velocity, the net force on the object is ____ and the weight of the object is e
Maslowich

When an object is falling and reaches a constant velocity, the net force on the object is <em>zero</em> (it's not accelerating), and the weight of the object is equal to <em>the force of air resistance against the object</em>.  (choice-D)

5 0
3 years ago
2. Suppose that a parallel-plate capacitor has circular plates with radius R = 30 mm and a plate separation of d = 5.0 mm. Suppo
seropon [69]

Answer:

The maximum value of the induced magnetic field is 2.901\times10^{-13}\ T.

Explanation:

Given that,

Radius of plate = 30 mm

Separation = 5.0 mm

Frequency = 60 Hz

Suppose the maximum potential difference is 100 V and r= 130 mm.

We need to calculate the angular frequency

Using formula of angular frequency

\omega=2\pi f

Put the value into the formula

\omega=2\times\pi\times60

\omega=376.9\ rad/s

When r>R, the magnetic field is inversely proportional to the r.

We need to calculate the maximum value of the induced magnetic field that occurs at r = R

Using formula of magnetic filed

B_{max}=\dfrac{\mu_{0}\epsilon_{0}R^2\timesV_{max}\times\omega}{2rd}

Where, R = radius of plate

d = plate separation

V = voltage

Put the value into the formula

B_{max}=\dfrac{4\pi\times10^{-7}\times8.85\times10^{-12}\times(30\times10^{-3})^2\times100\times376.9}{2\times130\times10^{-3}\times5.0\times10^{-3}}

B_{max}=2.901\times10^{-13}\ T

Hence, The maximum value of the induced magnetic field is 2.901\times10^{-13}\ T.

7 0
3 years ago
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