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3 years ago

How to use the gcf and distributive property to find each some: 32+48, 15+57, 98+14, 55+88

Mathematics

1 answer:

adoni [48]3 years ago

7 0

Answer:

For the first two:

16(2+3)

3(5+19)

Step-by-step explanation:

To find the gcf, you must list the factors of both numbers, and whichever one is greatest, you would put on the outside. Like 16 is the gcf of 32 and 48, so that number remains on the outside. Now, for the inside numbers, 16 times what equals 32? 16 times 2. 16 times what equals 48? 16 times 3 equals 48. Put those in the parenthesis, and put an addition sign in between them.

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3) 150% of what number is 63?

blagie [28]

Answer:

Step-by-step explanation:

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2 years ago

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A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor

Leno4ka [110]

Answer:

$C=120/2=60$

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

$P(X=0)=0.98^20$

$P(X=0)=0.668$

$P(X=1)=0.02*20*0.98^19$

$P(X=1)=0.272$

$P(X=2)=0.02^2*20*0.98^18$

$P(X=2)=0.053$

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

$C=120/2=60$

7 0

3 years ago

I need to know how to solve this

dedylja [7]

Answer:

Step-by-step explanation:

I think you have to call a = 14/32 and b = 7/4

3a = 3 * 14/32 = 42/32

b = 1 3/4 = (4 + 3)/4 = 7/4

42/32 // 7/4 Invert and multiply

42/32 * 4/7 Cancel 4 into 32 and 7 into 42

6/8 = 3/4

I make the answer C

3 0

3 years ago

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HELP PLEASE ASAP

olga2289 [7]

Answer: a) degree and sign

b) end behavior: left side → +∞, right side → -∞

c) x-intercepts: x = -1.3, 0.3, 1.0

Step-by-step explanation:

end behavior can be determined by two things:

1) the degree of the polynomial:

if the degree is an even number, then the end behavior will be the same for both the left and right sides.
if the degree is an odd number, then the end behavior will be different for both the left and right sides.

2) the sign of the leading coefficient:

If the leading coefficient is positive, then the end behavior of the right side goes to positive infinity
If the leading coefficient is negative, then the end behavior of the right side goes to negative infinity

W(x) = -5x³ + 7x - 2

Degree: 3 (odd)

Leading Coefficient: negative

So, end behavior is: right side goes to negative infinity, right side goes to positive infinity.

See attachment for x-intercepts. I set the x-axis to represent tenths