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3 years ago

Please help, Factored form

Mathematics

2 answers:

IrinaK [193]3 years ago

5 0

Answer:

B. ( 2x +3)(x-5)

Explanation:

A fully factored form means the given number or polynomial is expressed as a product of the simplest possible form.

mestny [16]3 years ago

3 0

Answer:

Step-by-step explanation:

Factored form means it is broken down into the expressions you would multiply to get the answer

You might be interested in

et mA = 40°. If B is a complement of A, and C is a supplement of B, find these measures. mB = ° mC = °

Free_Kalibri [48]

Alright, lets get started.

We have given angle A = 40°

We are also given angle B is complement of A.

Complementary angles are two angles whose sum is 90, it means

angle B = $90- A$

angle B = $90 - 40$

angle B = 50° Answer

Now given, angle C is supplement of angle B.

Supplementary angles are two angles whose sum is 180°.

Means angle C = $180 - B$

angle C = $180 - 50$

angle C = 130° : Answer

Means angle B = 50° and angle C = 130°

Hope it will help :)

5 0

3 years ago

RideAnS [48]

Answer:

4.5 ft

Step-by-step explanation:

Given that the two fugures in the question above are similar, it means they have the same shape, even though they are if different sizes, the ratio of their corresponding sides are proportional. Thus,

18/x = 8/2

Let's solve for x as required.

We have,

18/x = 8/2

=>Cross multiply:

18 × 2 = 8 × x

36 = 8x

=>Divide both sides by 8

36/8 = x

4.5 = x

x = 4.5 ft

The first option is our answer = 4.5 ft

5 0

3 years ago

Given that a = 2,5= 2 and C = -1 work out 2b – 3ac

poizon [28]

Step-by-step explanation:

2b-3ac

=2×2-3×2×(-1)

= 4+6

=10

6 0

3 years ago

Find the solution of the initial value problem dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago

A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take

Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - α)% confidence interval for population proportion P is:

$CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}$

The information provided is:

x = number of students who responded as"yes" = 70

n = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

$p=\frac{x}{n}$

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0

3 years ago

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