The answer to the question is C
        
                    
             
        
        
        
Hello,  Segment AP is congruent to segment CP.
        
             
        
        
        
Https://www.khanacademy.org/math/geometry-home/geometry-shapes/angles-with-polygons/v/sum-of-interior-angles-of-a-polygon
        
             
        
        
        
Answer:
   about 252.78 ft
Step-by-step explanation:
Define angle QMP as α. Then ...
   MN = 60·sin(α)
   NP = 60·cos(α)
   area MPN = (1/2)(MN)(NP) = 1800sin(α)cos(α)
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   PQ = 60tan(α)
   area MPQ = (1/2)(MP)(PQ) = 1800tan(α)
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The ratio of areas is 2.5, so we have ...
   1800tan(α) = 2.5·1800sin(α)cos(α)
   1 = 2.5cos(α)² . . . . . . divide by 1800tan(α)
   cos(α) = √0.4 . . . . . . solve for cos(α)
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Then the perimeter is ...
   Perimeter = MN +NP +PQ +QM = 60sin(α) +60cos(α) +60tan(α) +60/cos(α)
   = 60(sin(α) +cos(α) +tan(α) +sec(α))
   = 60(0.774597 +0.632456 +1.224745 +1.581139)
   = 60(4.212936) = 252.776
The perimeter of the trapezoid is about 252.776 feet.
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With perhaps a little more trouble, you can find the exact value to be ...
   perimeter = (6√10)(7+√6+√15)
 
        
             
        
        
        
Y= 1/2x +4
hopes this helps!