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DedPeter [7]
4 years ago
12

Differences between distance and displacement.​

Physics
1 answer:
fiasKO [112]4 years ago
7 0
It is a vector quantity
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Quanto tempo deve ficar ligado um ferro eletrico de 1000 w para que tenha o mesmo consumo de energia que um chuveiro de 4400 w q
Cerrena [4.2K]

Answer:

Thus, the time for the first lamp is 44 minutes.

Explanation:

Power of first lamp, P' = 1000 W

Power of second lamp, P'' = 4400 W

time for second lamp, t'' = 10 minutes

Let the time for first lamp is t'.

As the energy is same, so,

P' x t' = P'' x t''

1000 x t' = 4400 x 10

t' = 44 minutes

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3 years ago
Which characteristic do arid and polar regions share?
Setler79 [48]

few plants

Explanation:

Arid and polar regions of the world typically have few plant species. The plant species in such environment are called xerophytes. They are plants that can live in an area with little to no precipitation.

  • Arid regions of the world are about the most driest in the world with very high diurnal temperature range.
  • Polar regions are frigid and cold all year round.
  • Both arid and polar regions have little to no precipitation all year round.
  • They have poor soils to support plant growth.
  • This is why they both have few plants.

Learn more:

Temperate and tropical climate brainly.com/question/10856870

#learnwithBrainly

8 0
3 years ago
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When a rubber ball is thrown against a wall, energy is transferred and transformed. Select the
Nikolay [14]

Answer:

B. When the ball is released, the thrower's arm transfers its energy to the ball.

3 0
3 years ago
A double slit that is illuminated with coherent light of wavelength 644 nm produces a pattern of bright and dark fringes on a sc
shutvik [7]

Answer:

2.77 cm

Explanation:

d = separation between the slits = 2783 x 10⁻⁹ m

\lambda = wavelength of coherent light = 644 nm = 644 x 10⁻⁹ m

D = Distance of the screen = 6 cm = 0.06 m

y_{n} = Position of nth bright fringe

Position of nth bright fringe is given as

y_{n} = \frac{nD\lambda }{d}  

for n = 2

y_{2} = \frac{nD\lambda }{d}  

y_{2} = \frac{(2)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}

y_{2} = 0.0278 m

for n = 4

y_{4} = \frac{nD\lambda }{d}  

y_{4} = \frac{(4)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}

y_{4} = 0.0555 m

Distance between 4th and 2nd bright fringes is given as

w = y_{4} - y_{2} = 0.0555 - 0.0278 = 0.0277 m

w = 2.77 cm

8 0
3 years ago
Questions 1
Aleonysh [2.5K]

Answer:

Radiant to Chemical

Explanation:

I think

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3 years ago
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