How can a small human retina detect objects larger than itself?

Suppose a point charge is located at the center of a spherical surface. The electric field at the surface of the sphere and the

emmasim [6.3K]

Answer:

<em>The flux through the sphere will remain the same, and the magnitude of the electric field will increase by four times.</em>

Explanation:

The electric flux is the number of electric field, passing through a given area. It is proportional to the electric field strength and the area through which this field passes.

If the radius of the sphere is halved, the area of the sphere will reduce by square of the reduction, which will be four times. The electric field lines will become closer together, or technically increase by a fourth of its initial value. The resultant effect is that the electric flux will remain the same.

If originally,

Φ = EA cos∅

where Φ is the electric flux through the sphere

E is the electric field on the sphere

A is the area of the sphere.

If the area of the sphere is reduced to half, then,

the area reduces to A/4,

and the electric field increases to be 4E on the sphere.

The flux now becomes

Φ = 4E x A/4 cos∅

which reduces to

Φ = EA cos∅

which is the initial electric flux on the sphere.

8 0

3 years ago

A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o

givi [52]

Answer:

$1.77\times 10^{-7}\ C/m^2$

0.000439077936334 m

Explanation:

q = Charge of electron = $1.6\times 10^{-19}\ C$

E = Electric field = $2\times 10^{4}\ N/C$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = $9.11\times 10^{-31}\ kg$

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

Electric flux is given by

$\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2$

The charge per unit area on the plates is $1.77\times 10^{-7}\ C/m^2$

Deflection is given by

$s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m$

The deflection is 0.000439077936334 m

7 0

3 years ago

Four identical 2.5 mF capacitors are connected together electrically. What is the greatest possible capacitance of the combinati

MrRa [10]

When capacitors are in PARALLEL, they add up. (like resistors in series)

If you connect these four capacitors in parallel, the combination behaves like a single capacitor of (4 x 2.5) = 10 mF.

That's the greatest capacitance you can make with these four pieces.

7 0

3 years ago

How can you remember meiosis 1 and meiosis 2

Marianna [84]

Answer:

Once you know the differences between meiosis 1 and 2, you will remember it easier.

Explanation:

Meiosis 1 starts with 1 diploid cell Meiosis 2 starts with 2 haploid cells,

each with a homologous pair

Meiosis 1 results in 2 daughter cells Meiosis 2 results in 4

7 0

3 years ago

Which of the following is not accurate when desçribing solids?

Kitty [74]

There are no inaccurate items on the list you provided.

And what does 'the following" mean anyway ?

7 0

4 years ago