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algol [13]
3 years ago
10

Ryan is a nine-year-old boy whose father wants him to be a soccer player. Ryan does not have an aptitude for soccer, and keeps f

ailing miserably at it. His father criticizes him in an attempt to motivate Ryan to play better. As per Erickson's psychosocial theory, what is a likely consequence of this criticism?
Physics
2 answers:
mihalych1998 [28]3 years ago
8 0
A bad life when Ryan is older and will criticize his kids
Solnce55 [7]3 years ago
5 0

Answer:

C) Ryan may develop an inferiority complex.

Explanation:

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nirvana33 [79]

decreasing

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3 years ago
Why is gasoline so flammable
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Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.




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8 0
4 years ago
Read 2 more answers
A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too
maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = 90\times 1.989\times 10^{30}\ kg

R_{f} = 10000+100 m

R_{sb} = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2

The acceleration is 2352645198509.9604 m/s²

4 0
3 years ago
A constant net force that has a magnitude of 135.5 N is exerted on a 26.7 kg object that is initially not moving. a. Draw a free
jek_recluse [69]

Explanation:

Given that,

Net force = 135.5 N

Mass = 26.7 kg

(a). We need to draw a free body diagram

A force is exerted on a object.

(b). We need to calculate the acceleration

Using formula of acceleration

a =\dfrac{F}{m}

a=\dfrac{135.5}{26.7}

a=5.07\ m/s^2

(c). We need to draw the sketch a position vs. time graph for the object.

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value into the formula

s=0+\dfrac{1}{2}\times5.07\times t^2

s=2.535 t^2

(d). We need to draw the sketch a velocity vs. time graph for the object.

Using equation of motion

v = u+at

Put the value into the formula

v=0+5.07t

v =5.07 t

(e). We need to calculate the distance travel in 8.82 s

Using equation of motion

s=ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}\times5.07\times(8.82)^2

s=197.20\ m

Hence, This is the required solution.

8 0
3 years ago
________ is a long-standing connection or bond with others.
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4 years ago
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