Answer:
One way is to add or remove a product or a reactant in a chemical reaction at equilibrium. When additional reactant is added, the equilibrium shifts to reduce this stress: it makes more product. When additional product is added, the equilibrium shifts to reactants to reduce the stress. :)
Explanation:I am not sure how to use data on here :(
Answer:
Order of increasing strength of intermolecular attraction:
> 
> 
> Ar
Explanation:
can form hydrogen bond as H atom is attached with electronegative atom O.
Rest three, , , Ar are non-polar molecules.
In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, has strongest intermolecular attractions.
Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.
Molecular size and mass of is high as compared to .
van der Waals intermolecular forces of attraction increases with increase in size.
Therefore,
Order of increasing strength of intermolecular attraction will be:
> > > Ar
Answer:
Question 2: Na3PO4, KOH; Question 3: Na3PO4, KOH
Explanation:
Question 2
The reactants in a chemical equation are the species on the left side of the reaction arrow.
Thus the reactants are Na3PO4, KOH (sodium phosphate and potassium hydroxide).
Question 3.
The products in a chemical equation are the species on the right side of the reaction arrow.
Thus the products are NaOH, K3PO4 (sodium hydroxide and potassium phosphate).
The answer is Boyle's law. Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at a constant absolute temperature.
That is; V α 1/P , at constant temperature and a fixed amount of the gas.
Such that V= k/P where k is a constant
