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katrin [286]
3 years ago
6

True or false, cilia and mucus help keep our lungs clean and healthy?

Chemistry
1 answer:
fiasKO [112]3 years ago
6 0

Answer:

It does. They trap particles so they don’t enter.

Explanation:

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A sample of oxygen gas is compressed from 30.6 L to 1.8 L at constant temperature pressure of 1.8 atm. Calculate the amount of e
ad-work [718]

Answer:

the change in the internal energy of the system is 3,752.67 J

Explanation:

Given;

initial volume of the gas, V₁ = 30.6 L

final volume of the gas, V₂ = 1.8 L

constant pressure of the gas, P = 1.8 atm

Energy released by the system, Q = 1.5 kJ = 1,500 J

Apply pressure-volume work equation, to determine the work done on the gas;

w = -PΔV

w = -P(V₂ - V₁)

w = - 1.8 atm(1.8 L - 30.6 L)

w = 51.84 L.atm

w = 51.84 L.atm x 101.325 J/L.atm

w = 5,252.67 J

The change in the internal energy of the system is calculated as;

ΔU = Q + w

Since the heat is given out, Q = - 1,500 J

ΔU = -1,500 J  +  5,252.67 J

ΔU = 3,752.67 J

Therefore, the change in the internal energy of the system is 3,752.67 J

3 0
3 years ago
If you put an egg on a sidewalk on a hot day in July and try to cook it, you are using
Naddik [55]
Thermal energy from the sun that has transferred to the sidewalk
6 0
3 years ago
15. The starting diol for this molecule is
victus00 [196]

<h2>Answer with explanation </h2>

<h3><em>The starting diol for this molecule is :-</em></h3><h3><em>The starting diol for this molecule is :-D) ethan-1,2-diol.</em></h3>

<em>Hope </em><em>my </em><em>answer </em><em>is</em><em> helpful</em><em> to</em><em> you</em><em> </em><em>☺️</em>

3 0
3 years ago
Consider the equation:
Dmitry [639]

Answer:1. Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. The rate constant (k) for the reaction is 3.50M^\frac{-1}{2}s^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

rate=k[CHCl_3]^x[Cl_2]^y

k= rate constant

x = order with respect to CHCl_3

y = order with respect to Cl_2

n = x+y= Total order

1. a) From trial 1: 0.0035=k[0.010]^x[0.010]^y  (1)

From trial 2: 0.0069=k[0.020]^x[0.010]^y   (2)

Dividing 2 by 1 :\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}

2=2^x,2^1=2^x therefore x=1.

b)  From trial 2: 0.0069=k[0.020]^x[0.010]^y   (3)

From trial 3: 0.0098=k[0.020]^x[0.020]^y   (4)

Dividing 4 by 3:\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}

1.4=2^y,2^{\frac{1}{2}}=2^y therefore y=\frac{1}{2}

rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. to find rate constant using trial 1:

0.0035=k[0.010]^1[0.010]^\frac{1}{2}  

k=3.50M^\frac{-1}{2}s^{-1}

5 0
4 years ago
The rate law for a reaction is rate=k[A][B] Which one of the following statements is false? The rate law for a reaction is Which
Andrews [41]

Answer: The reaction is first order overall.

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

For the given rate law:

Rate=k[A]^1[B]^1

x = 1= order with respect to A

y =1=  order with respect to B

n =( x+y)= (1+1) = 2 = Total order

a)  If [A] is doubled, the reaction rate will increase by a factor of 2: True

Rate'=k[2A]^1[B]^1

Rate'=k[2]^1[A]^1[B]^1

Rate'=[2]^1\times Rate

Rate'=[2]\times Rate

b) The reaction is first order overall: False

The overall order is 1+1= 2.

c)  k is the reaction rate constant: True

Rate=k[A]^x[B]^y

k= rate constant

d) The reaction is first order in [B]: True

For the given rate law:

Rate=k[A]^1[B]^1

x = 1= order with respect to A

e) The reaction is first order in [A]: True

For the given rate law:

Rate=k[A]^1[B]^1

y =1=  order with respect to B

3 0
3 years ago
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