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bazaltina [42]
3 years ago
11

The formula is used to calculate the yield of a reaction.

Chemistry
2 answers:
creativ13 [48]3 years ago
6 0

Answer;:

Theoretical yield depends on limiting reagent.

Theoretical yield: no of moles of limiting reagent x molar mass of product

Percentage yield= observed yield x100/ theoretical yield

frosja888 [35]3 years ago
5 0
<span>The theoretical yield for a reaction is calculated based on the limiting reagent. This allows researchers to determine how much product can actually be formed based on the reagents present at the beginning of the reaction.</span> <span>The actual yield will never be 100 percent due to limitations.</span>

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I need help understanding this problem and the answer.
victus00 [196]

Answer:-

1440 cases

Explanation: -

We are told that 1 pallet = 45 bundles.

We are also told that 1 bundle = 32 cases.

We need to find how many cases are there in 1 pallet.

1 pallet = 45 bundles (First conversion factor)

= 45 x 32 cases (second conversion factor)

=1440 cases

Thus we see that 1 pallet has 1440 cases. We needed to use two conversion factors for this, first to convert pallet to bundle and second to convert bundle to cases.

5 0
3 years ago
The total volume required to reach the endpoint of a titration required more than the 50 mL total volume of the buret. An initia
Margaret [11]

Answer:

The endpoint volume is 50.52 ±  0.14 mL

Explanation:

In a titration always is necessary to subtract the blank volume to the titrant volume to obtain the real volume of the titrant. Thus in this case, the total endpoint volume is the sum of the initial volume delivered and the second volume delivered, minus the blank volume:

V = (49.16±0.06 mL) + (1.69±0.04 mL) - (0.33±0.04 mL)

V = (49.16 + 1.69 - 0.33) ± (0.06+0.04+0.04) mL

V = 50.52 ±  0.14 mL

It is necessary to consider the sum of the errors too.

7 0
3 years ago
QUESTION 3 A series of electrolytic deposition experiments is conducted. In each case, 10.0 Faradays is passed through the indiv
Neporo4naja [7]

The greatest molar amount of metal product is obtained from silver (1) nitrate.

Let us determine the mass of metal obtained in each case.

For La^3+;

La^3+ + 3e ----> La

1 mole of La is deposited by 3F

x moles of La is deposited by 10 F

x = 1 × 10/3

x = 3.33 moles

For Zn^2+;

1 mole Zn^2+ is deposited by 2F

x moles of Zn^2+ is deposited by 10 F

x = 5 F

For Ag^+

1 mole of Ag^+ is deposited by 1 F

x moles of Ag^+ is deposited by 10 F

x = 10 moles

For Ba^2+;

1 mole of Ba^2+ is deposited by 2 F

x moles of Ba^2+ is deposited by 10 F

x = 5 moles

Learn more: brainly.com/question/967776

6 0
2 years ago
Which Group is in the second column of the periodic table?
Misha Larkins [42]

Answer:

Hey there!

That would be the alkaline earth metals.

Hope this helps :)

3 0
3 years ago
Read 2 more answers
Conclusion of electrolysis for grade 8th
vlabodo [156]

The conclusion from these figures is that hydrogen should be produced at the cathode and oxygen at the anode from the electrolysis of water—which is at variance with the experimental observation that zinc metal is deposited and bromine is produce

6 0
3 years ago
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