About 2 gallons. (I got 1.92592592593)
Answer:
15.0 g
Explanation:
Step 1: Given and required data
- Heat used to melt a sample of ice (Q): 5.01 kJ
- Latent heat of fusion of water (ΔH°fus): 334 kJ/kg
Step 2: Calculate the mass (m) of water
334 kJ are required to melt 1 kg of ice at 0°C (melting point of water). We can calculate the mass of ice melted by 5.01 kJ using the following expression.
<em>Q = ΔH°fus × m</em>
m = Q / ΔH°fus
m = 5.01 kJ / (334 kJ/kg)
m = 0.0150 kg = 15.0 g
Avagadros constant states that there are 6.022 x 10²³ units in 1 mol of substance.
These units could be atoms that make up an element, or molecules making up a compound or ions as well.
1 mol of O₂ contains - 6.022 x 10²³ molecules of O₂
molecular mass of O₂ is (16*2) = 32 g/mol
1 mol of O₂ weighs = 32 g
Therefore in 32 g of O₂ - 6.022 x 10²³ O₂ molecules
gas tank contains O₂ weighing 650 g
in 1 g - 6.022 x 10²³/32 molecules
in 650 g - 6.022 x 10²³/32 * 650
= 2.96 x 10²² molecules of O₂