Answer:
The answer to your question is 80.3%
Explanation:
Data
Percent by mass of F
molecules NF₃
Process
1.- Calculate the molar mass of nitrogen trifluoride
molar mass = (1 x 14) + (19 x 3)
= 14 + 57
= 71 g
2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.
71 g of NF₃ ------------------ 100%
57 g of F ------------------- x
x = (57 x 100)/71
x = 5700 / 71
x = 80.3%
3.- Conclusion
Fluorine is 80.3% by mass of the molecule NF₃
The new temperature : 11.56 °C
<h3>Further explanation </h3>
Boyle's law and Gay Lussac's law

P1 = initial gas pressure (N/m² or Pa)
V1 = initial gas volume (m³)
P2 = final gas pressure
V2 = final gas volume
T1 = initial gas temperature (K)
T2 = final gas temperature
V₁=4.39 L
T₁=44+273=317 K
P₁ = 729 torr = 0,959211 atm
V₂=3.78 L
P₂= 1 atm

When electrons are added to the outermost shell of a carbon atom, it forms an anion.
Ain't is the correct answer