Answer:Student 4
Explanation: Because if the mountain lions, coyotes, and bobcats decrease they arent enough to prey on the deer which causes the deer population to be able to reproduce over time.
 
        
             
        
        
        
Earth’a temperature was too high for solid rock to form. 
 
        
                    
             
        
        
        
Answer:
Nocturnal animals are important pollinators. What niche do they specifically fill? They eat the nectars of angiosperm flowers.
Explanation:
 
        
             
        
        
        
Answer:
D) as we travel southward from the North Pole.
Explanation:
Species richness is the number of different species in a particular community. If we found 30 species in one community, and 300 species in another, the second community would have much higher species richness than the first.
Communities with the highest species richness tend to be found in areas near the equator, which have lots of solar energy (supporting high primary productivity), warm temperatures, large amounts of rainfall, and little seasonal change. Communities with the lowest species richness lie near the poles, which get less solar energy and are colder, drier, and less amenable to life. This pattern is illustrated below for mammalian species richness (species richness calculated only for mammal species, not for all species). Many other factors in addition to latitude can also affect a community's species-richness.
 
        
                    
             
        
        
        
Answer:
The t-test 
Explanation:
<em>The researcher should use a t-test to compare the two means and check if they are significantly different from each other.</em>
In using the t-test, both null (H0) and alternate (H1) hypothesis are made such that:
Thereafter, the value of t is calculated and compared to its critical value on the table. The formula for calculating the t goes thus:
  
 
where, Y1 = mean of population 1, Y2 = mean of population 2, S1 = variance of population 1, S2 = variance of population 2, n1 = number of individuals in population 1 and s2 = number of individuals in population 2.
<em>At the end of the day, if the calculated t value is more than the critical value of t, the H0 is rejected and it shows that the two means are significantly different. Otherwise, the H0 is accepted and this shows that there is not significant difference between the mean of population 1 and that of 2.</em>