Answer:
A food chain is a representation of what eats what in an ecosystem.
A combination of food chains is termed as a food web.
Example of two food chains in a food web are :
Example No 1:
Plant----- Grasshopper------ Frog---snake--- bacteria
Example No 2:
Plant---- rabbits---- fox---- bacteria
In a food chain, producers are usually plants and algae which are able to make their own food. Consumers feed on the plants. In example no 1, grasshoppers are primary consumers, frogs are secondary consumers, snakes are tertiary consumers.
In example no 2,plants are producers, rabbits are primary consumers and foxed are secondary consumers.
Decomposers are organisms that feed on the dead organisms in a food chain. In both the examples of food chain, bacteria are the decomposers.
Answer:
Both gene expression and DNA micro array study about the expression of gene during different stages of development.
Explanation:
The main purpose of gene expression studies is to determine the level of mRNA expressed at different stages of transcription in a tissue or at different stages of cellular development. If a gene is not “ON” during synthesis of RNA and protein, then the desired proteins are not produced. Such studies allow us to turn on such genes.
DNA microarray assays easily identify and determine the network of gene expression across the entire genome. The common application of DNA microarray include – mutation analysis and detection, assessment of gene cop, immunoassays etc.
The egg is produced by the female part the "ovaries", then sent down to the fallopian tube during sexual reproduction which then where the sperm and egg meet which then forms a baby that grows in the uterus for 280 days or 40 weeks. :)
Once an egg is fertilized by a sperm, a zygote is formed. The zygote divides into multiple cells in a process known as cleavage, triggering the beginning of embryonic differentiation. ... Cells in these three layers will give rise to different parts of the organism. The endoderm eventually becomes the gut.Mar 3, 2011
Answer: and Explanation:
A.)The reason for the different products of glycogen breakdown in the two tissues is that glucose 6-phosphotase which is
a known enzyme that brings about hydrolysis of glucose 6-phosphate as a result of the creation of a phosphate group and free glucose is not available in heart and skeletal muscle, therefore,any glucose 6-phosphotase that is produced will just enters the glycolytic pathway and get converted to lactate through pyruvate, in the absence of Oxygen O2.
B) Whenever a situation involving fight or flight arises, the concentration of glycolytic precursors becomes high in order to prepare for muscular activity. Since the membrane is impermeable to any charged species, and at the same time glucose 6-phosphotase enzyme cannot be moved through the glucose transporter, then there cannot be a release of Phosphorylated intermediates from the cell. The blood glucose level must be maintained by the liver by releasing of glucose.
glucose that is later formed from glucose 6-phosphotase then enters the bloodstream.
