Answer:
maximum force (in N) can you exert horizontally on the crate without moving it = 564.075 N
Explanation:
Given data:
mass m= 115 kg
coefficient of friction μ =0.5
according to newton law of motion the net force acted on body is given by

here the body is in rest ,

N= it is the normal reaction force
N= mg = 115×9.81
therefore,

Answer:
2m/s²
Explanation:
Given parameters:
Net force on the car = 2000N
Acceleration = 4m/s²
Unknown:
Acceleration of a car twice the mass = ?
Solution:
Let us first find the mass of the car;
Force = mass x acceleration
Mass =
Mass =
= 500kg
Now,
whose mass is twice that of the car
Mass of the new car = 2 x 500 = 1000kg
So;
Acceleration =
Acceleration =
= 2m/s²
B) 7.87 m/s
The gravitational pull is the rate of change of velocity which is the acceleration. Formula for acceleration is;

Given:
• Initial velocity = 0m/s; I dropped the ball, and didn't throw it, so it was at rest firstly
• Time taken = 2.40s
• Acceleration = 3.28m/s^2
We're require to find the final velocity, at which the ball hit the ground with. Ignoring air resistance, keep in mind that the velocity of an object increases as it comes closer to the ground.


Net Force = mass x acceleration
3500=1,000a
So a= 3500/1000
a=35/10
a=3.5 m/s^2