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olga2289 [7]
3 years ago
12

A planet of mass 7.00 1025 kg is in a circular orbit of radius 6.00 1011 m around a star. The star exerts a force on the planet

of constant magnitude 6.51 1022 N. The speed of the planet is 2.36 104 m/s.
(a) In half a "year" the planet goes half way around the star. What is the distance that the planet travels along the semicircle?
distance = m
(b) During this half "year", how much work is done on the planet by the gravitational force acting on the planet?
work = J
(c) What is the change in kinetic energy of the planet?
?K = J
(d) What is the magnitude of the change of momentum of the planet?
Physics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

A) 1.88 * 10^17 m

B) 1.22 * 10^34 J

C) 1.95 * 10^34 J

Explanation:

Parameters given:

Mass of planet = 7.00 * 10^25 kg

Radius of orbit = 6.00 * 10^11 m

Force exerted on planet = 6.51 * 10^22 N

Velocity of planet = 2.36 * 10^4 m/s

A) The distance traveled by the planet is half of the circumference of the orbit (which is circular).

The circumference of the orbit is

C = 2 * pi * R

R = radius of orbit

C = 2 * 3.142 * 6.0 * 10¹¹

C = 3.77 * 10¹² m

Hence, distance traveled will be:

D = 0.5 * 3.77 * 10¹²

D = 1.88 * 10 ¹² m/s

B) Work done is given as:

W = F * D

W = 652 * 10²² * 1.88 * 10¹¹

W = 1.22 * 10³⁴ J

C) Change in Kinetic energy is given as:

K. E. = 0.5 * m * v²

K. E. = 0.5 * 7 * 10^25 * (2.36 * 10^4)²

K. E. = 1.95 * 10³⁴ J

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Answer: Symbol A

Explanation:

The four symbols described here represent:

- Symbol A shows two dots and a line draw from one not connected to the other.  --> this is an open switch. A switch is component of a circuit that is used to open/close the circuit in order to interrupt/allow the flow of current through the circuit. In this case, the switch is open, since the line does not connect the second dot.

- Symbol B shows two dots and a line draw from one connected to the other.  --> this is the symbol used to represent the switch when it is closed, so it is a closed switch.

- Symbol C shows vertical lines in the pattern long, short, long, and short with a plus and minus symbol on it. --> this symbol represents a battery, which consists of two or more cells and provides the electromotive force that pushes the electrons along the circuit.

Therefore, the correct symbol representing the open switch is

Symbol A

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a model of a plane in different parts of the atmosphere uses a scale of 1:4,000. if a plane flies at an altitude of 2,000 feet,
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Explanation:

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Aleonysh [2.5K]

Answer:

1. 10.5 Kg

2. s/g

Explanation:

1. Determination of the mass of gasoline

Density of gasoline = 0.7 Kg/L

Volume of gasoline = 15 L

Mass of gasoline =?

The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance can be expressed as:

Density = mass / volume

With the above formula, we can obtain the mass of the gasoline as follow:

Density of gasoline = 0.7 Kg/L

Volume of gasoline = 15 L

Mass of gasoline =?

Density = mass / volume

0.7 = Mass of gasoline / 15

Cross multiply

Mass of gasoline = 0.7 × 15

Mass of gasoline = 10.5 Kg

2. Density has various units some are listed below:

I. Kilogram per litre (Kg/L)

II. Kilogram per cubic metre (Kg/m³)

III. Milligram per millilitre (mg/mL)

IV. Gram per millilitre (g/mL)

V. Gram per cubic centimetre (g/cm³)

Considering the options given in the question above, it is evident that second per gram (s/g) is not a unit of density because density is mass per unit volume.

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3 years ago
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Answer:

Here is an image attached with similar questions.

The correct answer is D where acceleration is function of time.

Explanation:

The force acting on the object is constant.

There is no change in the application of forces.

And we know that Force is the product of acceleration and masses.

Newtons second law: F=m\times a

Regarding mass we know that it can neither be created nor destroyed.

So in F=m \times a we have two constant terms, constant divided by constant will give the same result as a=\frac{Force}{mass}

There is no change in acceleration (a) with respect to time (t).

So the most appropriate graph where time (t) is changing on x-axis but acceleration doesn't changes is D.

The graph will be similar to y=any\ constant and will be horizontal to the x-axis.

Option D depicts the same.

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