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tamaranim1 [39]
3 years ago
11

If an object was accelerating at 10 m/s2, and a mass of 1 kg, what was size of the force acting on the object?

Physics
1 answer:
ryzh [129]3 years ago
7 0

Answer:

10 N

Explanation:

f = ma

= 10m/s^2 * 1 kg

=10N

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8 0
4 years ago
Awave has a period of 1. What is its frequency?
Andrei [34K]

Answer:

Frequency, f = 1 unit

Explanation:

It is given that,

Period of the wave, T = 1 unit

We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :

T=\dfrac{1}{f}

Or

f=\dfrac{1}{T}

f=\dfrac{1}{1\ units}

f = 1 unit

So, the frequency of the wave is 1 unit. Hence, this is the required solution.

4 0
4 years ago
If the mass of the cart was increased but the hanging mass remained the same, how would the acceleration be affected? Explain ho
Margaret [11]

Answer:

It is always said that mass is same everywhere.

6 0
3 years ago
3. A fighter jet covers a distance of 895m while accelerating from 22m/s to 35m/s. How long (in
larisa86 [58]

Answer:

31.404 seconds

Explanation:

To answer this equation, SUVAT is your best option utilizing and rearranging the known values to solve for the unknown.

here we have the values for

s=895

u=22

v=35

t= the unknown value

in this instant the equation s=0.5 x (u+v)t is the best equation to use

so we sub in the known values

895=0.5 x (22+35)t

rearrange to solve for t

895=28.5t

895/28.5=t

t=31.404 seconds (rounded to 3 decimal places)

6 0
3 years ago
Your local AM radio station broadcasts at a frequency of f = 1100 kHz. The electric-field component of the signal you receive at
Lina20 [59]

Answer:

(a) 272.73 m

(b) 0.338 N/C

Explanation:

frequency, f = 1100 kHz = 1100 x 1000 Hz

E(t) = Eo Sin(2πft)

Eo = 0.62 N/C

(a) Velocity of light, c = 3 x 10^8 m/s

wavelength, λ = c / f = (3 x 10^8) / (1100000) = 272.73 m

Thus, the wavelength is 272.73 m.

(b) at t = 3.1 microsecond = 3.1 x 10^-6 s

E = Eo Sin (2 π ft)

E = 0.62 Sin (2 x 3.14 x 1100 x 10^3 x 3.1 x 10^-6)

E = 0.62 Sin (21.4148)

E = 0.62 x 0.5449 = 0.338 N/C

Thus, the electric field at t = 3.1 microsecond s 0.338 N/C.

6 0
3 years ago
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