Answer:
![10942249.24 m^{-1}](https://tex.z-dn.net/?f=10942249.24%20m%5E%7B-1%7D)
Explanation:
Rydberg's formula is used to describe the wavelengths of the spectral lines of chemical elements similar to hydrogen, that is, with only one electron being affected by the effective nuclear charge. In this formula we can find the rydberg constant, knowing the wavelength emitted in the transcision between two energy states, we can have a value of the constant.
![\frac{1}{\lambda}=Z^2R(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%3DZ%5E2R%28%5Cfrac%7B1%7D%7Bn%5E2_%7B1%7D%7D-%5Cfrac%7B1%7D%7Bn%5E_%7B2%7D%5E2%7D%7D%29)
Where
it is the wavelength of the light emitted, R is the Rydberg constant, Z is the atomic number of the element and
are the states where
.
In this case we have Z=1 for hydrogen, solving for R:
![R=\frac{1}{\lambda}*(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})^{-1}\\R=\frac{1}{658.9*10^{-9}m}*(\frac{1}{2^2}-\frac{1}{3^2}})^{-1}\\R=1.52*10^6m^{-1}*(\frac{36}{5})=1.09*10^7 m^{-1}=10942249.24m^{-1}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1%7D%7B%5Clambda%7D%2A%28%5Cfrac%7B1%7D%7Bn%5E2_%7B1%7D%7D-%5Cfrac%7B1%7D%7Bn%5E_%7B2%7D%5E2%7D%7D%29%5E%7B-1%7D%5C%5CR%3D%5Cfrac%7B1%7D%7B658.9%2A10%5E%7B-9%7Dm%7D%2A%28%5Cfrac%7B1%7D%7B2%5E2%7D-%5Cfrac%7B1%7D%7B3%5E2%7D%7D%29%5E%7B-1%7D%5C%5CR%3D1.52%2A10%5E6m%5E%7B-1%7D%2A%28%5Cfrac%7B36%7D%7B5%7D%29%3D1.09%2A10%5E7%20m%5E%7B-1%7D%3D10942249.24m%5E%7B-1%7D)
This value is quite close to the theoretical value of the constant ![R=10967758.34 m^{-1}](https://tex.z-dn.net/?f=R%3D10967758.34%20m%5E%7B-1%7D)
Answer:Minerals are naturally occurring inorganic substances, often with a crystalline structure. They are composed largely of the most abundant elements in the Earth's crust, silicon and oxygen, coupled with metals or the metallic elements of iron, calcium, sodium, potassium, and magnesium.
Explanation:Hope this helped u also may i plz have brainlist plz only if u wanna give me brainlist though. Have an great day kind sir or ma'am!
Speed of man towards West =2.5 m/s
Time to travel in the given direction = 1200 s
Total displacement towards west
![d_1 = v_1 t](https://tex.z-dn.net/?f=d_1%20%3D%20v_1%20t)
![d_1 = 2.5 \times 1200 = 3000 m](https://tex.z-dn.net/?f=d_1%20%3D%202.5%20%5Ctimes%201200%20%3D%203000%20m)
Now speed of man towards East = 1 m/s
time to travel in east direction = 500 s
total displacement towards East
![d_2 = v_2 t](https://tex.z-dn.net/?f=d_2%20%3D%20v_2%20t)
![d_2 = 1 \times 500 = 500 m](https://tex.z-dn.net/?f=d_2%20%3D%201%20%5Ctimes%20500%20%3D%20500%20m)
Now total displacement will be
![d = d_1 - d_2](https://tex.z-dn.net/?f=d%20%3D%20d_1%20-%20d_2)
![d = 3000 - 500 = 2500 m](https://tex.z-dn.net/?f=d%20%3D%203000%20-%20500%20%3D%202500%20m)
so it is 2500 m towards west
Answer:
the correct answer is 273.2 k