Time period of pendulum is given by
Here,
L is length
g is acceleration due to gravity
Therefore we can determine that the period of the pendulum is directly proportional to the square root of the length of the rope.
Therefore, it is necessary to increase the length of the rope to increase the period so that it counts the seconds more slowly. The correct answer is A.
Answer:
3.6*10^18s
Explanation:
To find the period of the satellite
We need to apply kephler's third law
Which is
MP² = (4π²/G) d³
d=semi-major axis which is the distance from center of moon = 98km+1740km = 1838km
where M= mass of the moon = 7.3x10^22kg
P=period
G=newtonian gravatational constant= 6.67x10^-11
To find the Period solve for P
P = √[(4π²/G M)xd³]
P=√(4 π²/6.67x10^-22*7.3x10^22kg) x (1.838x10^6m)³]
= 3.6*10^18s
Answer: 29.5 days
The waxing moon phase comprises three separate moon phases: the Waxing Crescent, First Quarter, and the Waxing Gibbous.
The current in the 50 Ω resistor is A) 1.2 A
Answer: D. Hydroelectric power
Explanation: Hydroelectric means water power (not exactly but "hydro" is water and electric is well self explanatory)
