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3 years ago

Instructions:Select all the correct answers.

2 answers:

7 0

Correct option - 2

As the golf ball hits the ground it exerts some force on the ground.In return the ground will exert an opposite and equal force on the golf ball.

Hope This Helps You!

melomori [17]3 years ago

6 0

The answer would be B: The ground exerts an equal force on the golf ball.

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Is there life on other planets ?

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Supposedly there is life on Mars but it’s early to say for sure

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2 years ago

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A rock is dropped from a bridge to the water below. It takes 2.40 s for the rock to hit the water (a) find the speed in m/s of t

Artyom0805 [142]

Answer: I think Its the Height is 11.76 Meters (38.582677 Feet) between the bridge and the ground

Explanation: Supposing that where not counting air resistance in the equation, the equation $D = ut+\frac{1}{2} at^{2}$ states that 1/2 multiplied by earths gravitational acceleration multiplied by the amount of time to reach the bottom: 2.4 seconds equals 11.76 meters of height between the bridge and the ground.

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1 year ago

What is the momentum of a bird with a mass of 0.018kg flying at 15m/s?

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0.27 kg-m/s

Explanation:

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2 years ago

It takes a minimum distance of 57.46 m to stop a car moving at 13.0 m/s by applying the brakes (without locking the wheels). Ass

vivado [14]

Answer:

The minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

Explanation:

We know by equation of motion that,

$v^{2}=u^{2}+2\cdot a \cdot s$

Where, v= final velocity m/sec

u=initial velocity m/sec

a=Acceleration m/ $Sec^{2}$

s= Distance traveled before stop m

Case 1

u= 13 m/sec, v=0, s= 57.46 m, a=?

$0^{2} = 13^{2} + 2 \cdot a \cdot57.46$

a = -1.47 m/ $Sec^{2}$ (a is negative since final velocity is less then initial velocity)

Case 2

u=29 m/sec, v=0, s= ?, a=-1.47 m/ $Sec^{2}$ (since same friction force is applied)

$v^{2} = 29^{2} - 2 \cdot 1.47 \cdot S$

s = 285.94 m

Hence the minimum stopping distance when the car is moving at

29.0 m/sec = 285.94 m

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