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Lorico [155]
3 years ago
13

Are all liquids able to conduct an electric current

Physics
1 answer:
Alona [7]3 years ago
6 0

The ions are able to carry electric current through a solution. Some liquids such as oil or alcohol do not form ions and do not conduct electricity. Vinegar is mostly water with a small amount of acetic acid in it. The acetic acid separates into ions on so that the solution conducts electricity.     BRAINLIST ME PEASE

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It opens or close the circuit​
gayaneshka [121]

Answer:

The person above me is right i had a test a couple of days ago and thats kinda what u put and got it right!

3 0
2 years ago
A particle starts from the origin at t = 0 with an initial velocity of 4.8 m/s along the positive x axis.If the acceleration is
tia_tia [17]

Answer:

Part a)

Velocity = 6.9 m/s

Part b)

Position = (3.6 m, 5.175 m)

Explanation:

Initial position of the particle is ORIGIN

also it initial speed is along +X direction given as

v_x = 4.8 m/s

now the acceleration is given as

\vec a = -3.2 \hat i + 4.6 \hat j

when particle reaches to its maximum x coordinate then its velocity in x direction will become zero

so we will have

v_f = v_i + at

0 = 4.8 - 3.2 t

t = 1.5 s

Part a)

the velocity of the particle at this moment in Y direction is given as

v_f_y = v_i + at

v_f_y = 0 + 4.6(1.5)

v_f_y = 6.9 m/s

Part b)

X coordinate of the particle at this time

x = v_x t + \frac{1}{2}a_x t^2

x = 4.8(1.5) - \frac{1}{2}(3.2)(1.5^2)

x = 3.6 m

Y coordinate of the particle at this time

y = v_y t + \frac{1}{2}a_y t^2

y = 0(1.5) + \frac{1}{2}(4.6)(1.5^2)

y = +5.175 m

so position is given as (3.6 m, 5.175 m)

5 0
3 years ago
When a 9.9 kg object is in free fall, it feels a force of 97.02 N. what is its acceleration?
Free_Kalibri [48]

The acceleration of an object in free fall is 9.8 m/s^2

Explanation:

We can solve the problem by using Newton's second law of motion, which states that:

F=ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the object in this problem, we have:

m = 9.9 kg is its mass

F = 97.02 N is the net force on the object

So, we can rearrange the equation to find its acceleration:

a=\frac{F}{m}=\frac{97.02}{9.9}=9.8 m/s^2

This value is actually known as acceleration of gravity (g), and it is the acceleration that any object in free fall has near the Earth's surface, regardless of its mass.

Learn more about Newton's second law here:

brainly.com/question/3820012

And about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

6 0
3 years ago
Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 1.80 cm from the axis to equal
Arturiano [62]

Answer:

The required angular speed ω of an ultra-centrifuge is:

ω = 18074 rad/sec

Explanation:

Given that:

Radius = r = 1.8 cm

Acceleration due to g = a = 6.0 x 10⁵ g

Sol:

We know that

Angular Acceleration = Angular Radius x Speed²

a = r x ω ²

Putting the values

6 x 10⁵ g = 1.8 cm x ω ²

Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²

6 x 10⁵ x 9.8 = 0.018 x ω ²

ω ² = (6 x 10⁵ x 9.8) / 0.018

ω ² =  5880000 / 0.018

ω ² =  326666667

ω = 18074 rad/sec

7 0
3 years ago
Your school science club has devised a special event for homecoming. You've attached a rocket to the rear of a small car that ha
Strike441 [17]

Answer:

Explanation:

Acceleration acts for 9 s and deceleration acts for 12 - 9 = 3 s.

Total distance covered = 990 m

initial velocity u = o

Distance covered while accelerating

s₁ = 1/2 a 9² where a is the acceleration

= 40.5 a

final velocity after 9 s

v = at = 9a

while decelerating

v² = u² - 5 x s₂

0 = (9a)² - 5 s₂

s₂ = 16.2 a²

Distance covered while decelerating = 16.2 a²

s₁ + s₂ = 990

40.5 a + 16.2 a² = 990

16.2 a² + 40.5 a - 990 = 0

a = 6.5

4 0
3 years ago
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