The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 12.0V (assuming circuit resistance is negligable) and it has a capacitance of 18.0μf or 18.0x10^-6f, therefore charge equals (18.0x10^-6)x12=2.16x10^-4C (Coulombs).
Answer:
The amount of mass that needs to be converted to release that amount of energy is 
Explanation:
From Albert Einstein's Energy equation, we can understand that mass can get converted to energy, using the formula
where 
= change in mass
c = speed of light = 
Making m the subject of the formula, we can find the change in mass to be
There fore, the amount of mass that needs to be converted to release that amount of energy is 1.122 X 10 ^-7 kg
When a neutron or a proton in the nucleus changes a gamma ray is produced (gamma rays are electromagnetic waves)
When an electron drops from a higher energy level to a lower energy level an electromagnetic wave is give off.
I'll tell you how I look at this, although I may be missing something important.
Position = x(t) = 0.5 sin(pt + p/3)
Speed = position' = x'(t) = 0.5 p cos(pt + p/3)
Acceleration = speed' = position ' ' = x ' '(t) = -0.5 p² sin(pt + p/3)
At (t = 1.0),
x ' '(t) = -0.5 p² sin( 4/3 p )
In order to evaluate this, don't I still have to know what 'p' is ? ?
I don't think it can be evaluated with the information given in the question.
