3 years ago

In three different experiments, the following results were obtained for the reaction

1 answer:

5 0

From the given observations,
You can see that as the concentration is doubled, half-life is halved.

That is,half-life is inversely proportional to concentration

As t( half-life) ~ 1/a^(n-1)

For this case n = 2,second order reaction.

R = k X a^n

Using the above formula you will get the rate and rate constant.

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